Electronics and Communication Engineering - Analog Electronics - Discussion
Discussion Forum : Analog Electronics - Section 2 (Q.No. 20)
20.
In following figure find VDSQ by assuming gate current is negligible for the p-channel JFET. (if IDQ = - 6 mA, RS = 0, VDD = -18 V, RD = 2 kΩ, IDSS = - 10 mA, IPO = - 3 V)
Answer: Option
Explanation:
By Appling KVL around drain source loop.
VDSQ = -18 - (-6). 2 x 103 = - 18 + 12 k x 10-3 
-6 V.
Discussion:
3 comments Page 1 of 1.
LOi Bi said:
6 years ago
By applying KVL:
VDSQ= VDD-IDQ* (RD+RS) , Since RS=0.
VDSQ= VDD-IDQ*RD.
VDSQ= -6v, Just substitute the given.
VDSQ= VDD-IDQ* (RD+RS) , Since RS=0.
VDSQ= VDD-IDQ*RD.
VDSQ= -6v, Just substitute the given.
Jsree said:
7 years ago
-6mA is Idq. In the first step, they took only -6.
Mae said:
8 years ago
Where does 10^-3 comes from?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers