Electronics and Communication Engineering - Analog Electronics - Discussion
Discussion Forum : Analog Electronics - Section 6 (Q.No. 23)
23.
The zener diode in the rectangular circuit shown in the figure has a zener voltage of 5.8 volts and a zener knee current of 0.5 mA. The maximum load current drawn from this circuit ensuring proper functioning over the input voltage range between 20 and 30 volts, is
Answer: Option
Explanation:
It is zener diode, hence 5.8 volt remain constant.
By applying KVL
30 = 1000 Imax + 5.8
Imax = 24.2 mA.
Discussion:
7 comments Page 1 of 1.
Shatrughn kumar said:
4 years ago
It must be 23.7. I too agree.
Midhun Joy said:
4 years ago
Yes, 23.7 is the right answer.
Gautamkumar said:
6 years ago
23.7 is the answer.
RANGOJU SEEMANTH said:
7 years ago
My answer is 13.7 mA because the load current has to remain constant. If input voltage increases load current also increasing instead of being load current constant as resistance is not varying. We have to take voltage source value as 20v instead of 30.
I(min)=Iz(min)+Io(max),
14.2 = 0.5 + Io(max).
I(min)=Iz(min)+Io(max),
14.2 = 0.5 + Io(max).
(1)
Sarat said:
9 years ago
Yes, knee current must be considered.
Girish reddy said:
1 decade ago
Explanation is just up to source current, hence if extended up to load current the answer is 23.7 mA.
Shailesh said:
1 decade ago
Answer = 23.7 mA.
Here calculation is incomplete.
For load current 24.2-0.5 = 23.7 mA where 0.5 mA is zener knee current.
Here calculation is incomplete.
For load current 24.2-0.5 = 23.7 mA where 0.5 mA is zener knee current.
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