Electronics and Communication Engineering - Analog Electronics - Discussion

5. 

A half wave diode circuit using ideal diode has an input voltage 20 sin ωt volts. Then average and rms values of output voltage are

[A]. and 10 V
[B]. and 10 V
[C]. and 5 V
[D]. and 5 V

Answer: Option B

Explanation:

and VC = 0.5 x 20 = 10 V.


D.Suganya said: (Jun 7, 2014)  
How to get vdc and rms value?

Geeta said: (Sep 10, 2014)  
How to get Vc value?

Yasobanta said: (Jan 20, 2015)  
Where to find 0.5?

Ram said: (Jan 31, 2015)  
vdc = vav = vm/pi.
vrms = vm/2.

Parth said: (Feb 9, 2015)  
For Full wave Diode Rectifier Vavg = 2Vm/pi and Vrms = Vm/root(2).

For Half wave Diode Vavg = Vm/pi and Vrms = Vm/2.

Raviraj said: (Mar 17, 2015)  
Isn't rms value = Vm/sqrt(2)?

Vinod said: (Jul 3, 2015)  
The average voltage value of the half wave rectifier = vm/pi.

Rajan said: (Jun 30, 2016)  
Actually for AC sine wave V(average) = (2/pi x Vpeak) and V(rms) = Vpeak/sqrt(2), but after the sine wave form past through the Diode with half rectified wave the formula changed slightly with V(dc) = V(average) = Vpeak/pi and V(rms) = 0.45xV(dc).

In this example Vpeak = 20,

So, Vdc = 20/pi and Vrms = 0.45x (20/pi), that is what I learnt from some ref material.

Keerthana said: (Jul 13, 2016)  
Can anyone give a better explanation to understand the solution?

Dinesh said: (Jan 20, 2017)  
In between source and load which type component is used to prevent return path in DC source.

Saivasanth said: (Jun 18, 2017)  
@Dinesh.

Capacitor is used as it blocks dc component.

Avishkarg said: (Dec 3, 2017)  
For HWR ckt. avg value=Vm/π and RMS value=Vm/2.
For FWR ckt avg value=2Vm/π and RMS value=Vm/√2.

Sriram said: (Aug 6, 2018)  
I think the answer should be 40/π.

Satish M said: (Sep 14, 2018)  
How to get the answer? Please, anyone, help me.

Aman Sajwan said: (Jan 10, 2019)  
Vdc =Vm/π, and Vrms=Vm/2.

Pen said: (Mar 8, 2019)  
For HWR;
Vrms = 1.57Vavg.

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