Electronics and Communication Engineering - Analog Electronics - Discussion

Discussion Forum : Analog Electronics - Section 1 (Q.No. 5)
5.
A half wave diode circuit using ideal diode has an input voltage 20 sin ωt volts. Then average and rms values of output voltage are
and 10 V
and 10 V
and 5 V
and 5 V
Answer: Option
Explanation:

and VC = 0.5 x 20 = 10 V.

Discussion:
20 comments Page 2 of 2.

Dinesh said:   9 years ago
In between source and load which type component is used to prevent return path in DC source.

Keerthana said:   9 years ago
Can anyone give a better explanation to understand the solution?

Rajan said:   9 years ago
Actually for AC sine wave V(average) = (2/pi x Vpeak) and V(rms) = Vpeak/sqrt(2), but after the sine wave form past through the Diode with half rectified wave the formula changed slightly with V(dc) = V(average) = Vpeak/pi and V(rms) = 0.45xV(dc).

In this example Vpeak = 20,

So, Vdc = 20/pi and Vrms = 0.45x (20/pi), that is what I learnt from some ref material.
(1)

Vinod said:   1 decade ago
The average voltage value of the half wave rectifier = vm/pi.

Raviraj said:   1 decade ago
Isn't rms value = Vm/sqrt(2)?

Parth said:   1 decade ago
For Full wave Diode Rectifier Vavg = 2Vm/pi and Vrms = Vm/root(2).

For Half wave Diode Vavg = Vm/pi and Vrms = Vm/2.

Ram said:   1 decade ago
vdc = vav = vm/pi.
vrms = vm/2.

Yasobanta said:   1 decade ago
Where to find 0.5?

Geeta said:   1 decade ago
How to get Vc value?

D.SUGANYA said:   1 decade ago
How to get vdc and rms value?


Post your comments here:

Your comments will be displayed after verification.