Electronics and Communication Engineering - Analog Electronics - Discussion

Discussion Forum : Analog Electronics - Section 1 (Q.No. 12)

Analog Electronics

12.

In figure, V_EB = 0.6 V, β = 99. Then V_C and I_C are

9.3 V and 1.98 mA respectively

4.6 V and 1.98 mA respectively

9.3 V and 0.02 mA respectively

4.6 V and 0.02 mA respectively

Answer: Option

Explanation:

V_C = 20 - 1.98 x 10^-3 x 5.4 x 10³ 9.3 V.

Discussion:

11 comments Page 2 of 2.

Karthik said: 7 years ago

What is 400/9?

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