Electronics and Communication Engineering - Analog Electronics - Discussion

Discussion Forum : Analog Electronics - Section 1 (Q.No. 12)

Analog Electronics

12.

In figure, V_EB = 0.6 V, β = 99. Then V_C and I_C are

9.3 V and 1.98 mA respectively

4.6 V and 1.98 mA respectively

9.3 V and 0.02 mA respectively

4.6 V and 0.02 mA respectively

Answer: Option

Explanation:

V_C = 20 - 1.98 x 10^-3 x 5.4 x 10³ 9.3 V.

Discussion:

11 comments Page 2 of 2.

Sandeep said: 1 decade ago

Why 400/9 is taken?

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