Electronics and Communication Engineering - Analog Electronics - Discussion
Discussion Forum : Analog Electronics - Section 3 (Q.No. 13)
13.
In the circuit of figure the diode
Answer: Option
Explanation:
Diode will always be reverse biased.
Discussion:
7 comments Page 1 of 1.
Nitin gehlot said:
1 decade ago
Diode will on when input is greater than 50 we. Input reaches to 50 we when the angle is 30 and back to 50 we when it will be 150 degree.
So for this time diode will on.
So answer is option D.
So for this time diode will on.
So answer is option D.
(1)
Saurabh kumar said:
5 years ago
For conducting diode:
Anode diode voltage is must greater than 50.
So,
100sinwt = 50v,
wt=sin^-1(50/100),
wt 30 degree.
So the diode will conduct only when wt > 30 and less than 150.
The answer will be option D.
Anode diode voltage is must greater than 50.
So,
100sinwt = 50v,
wt=sin^-1(50/100),
wt 30 degree.
So the diode will conduct only when wt > 30 and less than 150.
The answer will be option D.
(1)
PARTH doshi said:
7 years ago
Can anyone explain? please.
Deep sharma said:
5 years ago
Please explain this question.
Sayan said:
3 years ago
No. The option C is correct.
Because if suppose diode is in forward bias then the voltage across resistor are will 50volts which causes the voltage drop in N junction is 100volts. It causes no conduction.
Because if suppose diode is in forward bias then the voltage across resistor are will 50volts which causes the voltage drop in N junction is 100volts. It causes no conduction.
AL FROM MAPUA U said:
3 years ago
@All.
Here, we can't directly subtract AC to DC voltage.
Convert 100 Vp AC to Valve by dividing it to π. That would be 31.83, which is way lower than the cathode voltage of 50V.
Here, we can't directly subtract AC to DC voltage.
Convert 100 Vp AC to Valve by dividing it to π. That would be 31.83, which is way lower than the cathode voltage of 50V.
Rohit Dubey said:
2 years ago
From 30 degree to 150 degree, the AC voltage will dominate the DC voltage.
So in that period, the Diode will be in forward bias, hence "D" option is correct.
So in that period, the Diode will be in forward bias, hence "D" option is correct.
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