Electronic Devices - Voltage Regulators - Discussion
Discussion Forum : Voltage Regulators - General Questions (Q.No. 15)
15.
If a peak rectified voltage for the full-wave filter circuit is 40 V, calculate the filter dc voltage if C = 75 
F and load current is 40 mA.
F and load current is 40 mA.Discussion:
8 comments Page 1 of 1.
Joel said:
1 decade ago
How to solve my friend?
(1)
Kiruthika said:
9 years ago
Anyone explain this, please.
Theo said:
9 years ago
Please, Can anybody explain this?
Jhey emm said:
9 years ago
This can be solved by:
40 - Ripple voltage.
Ripple voltage = I/240 * sqrt 3 * C.
40 - Ripple voltage.
Ripple voltage = I/240 * sqrt 3 * C.
Shishir said:
8 years ago
We know that,
Vdc = Vmax - Idc/4fc.
= 40- (40*10^-3)/(4*(50hz)*75*10^-6).
= 40-2.666,
= 37.33 V.
Vdc = Vmax - Idc/4fc.
= 40- (40*10^-3)/(4*(50hz)*75*10^-6).
= 40-2.666,
= 37.33 V.
(2)
Lily said:
7 years ago
Thanks for the answer.
(2)
Rahul said:
7 years ago
Thanks @Shishir.
Oliver Pogs said:
6 years ago
Formula is :
V(dc) = Vm - (4.17*I(dc)/C), I(dc) in mA and C in uF.
V(dc) = Vm - (4.17*40/75).
V(dc) = 37.78 V.
V(dc) = Vm - (4.17*I(dc)/C), I(dc) in mA and C in uF.
V(dc) = Vm - (4.17*40/75).
V(dc) = 37.78 V.
(3)
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