Electronic Devices - Semiconductors - Discussion
Discussion Forum : Semiconductors - General Questions (Q.No. 1)
1.
A silicon diode measures a low value of resistance with the meter leads in both positions. The trouble, if any, is
Discussion:
40 comments Page 4 of 4.
Sudhir pandey said:
1 decade ago
The answer is diode is internally short because in forward bias diode behave as short ckt, so we know that in short circuit resistance is low.
Fathima said:
1 decade ago
Ya mohana is correct.
Palkaushil said:
1 decade ago
Because A good silicon diode has small resistance in forward bias and infinite resistance in reverse bias. So, only internally shorted diode will give the Resistance value in both direction.
Mohana ragadeepthi said:
1 decade ago
In forward bias condition the diode starts conducting. That means there is flow of current (charge carriers) and the diode conducts to maximum and itoffers very low resistance. (we all know that conduction is inversely proportional to resistance).
S CHAKRABORTY said:
1 decade ago
If the diode is internally short ten ideally it should sow Zero resistance in both forward and reverse bias .As no diode can be ideal so it is showing very less resistance.
Rash said:
1 decade ago
Short circuted diode will behave like a superconductor and will melt.
Sahana949 said:
1 decade ago
It is not exactly short in forward bias it offers very very less resistance so we assume it to be a short.
Jeetender nath said:
1 decade ago
If internally short, how its show resistance becoz, incondition of short, the resistance should zero.
M.senthil kumar said:
1 decade ago
The answer is diode is internally short. So it behave like a conductor so it shows low resistance value.
Sadaf parwaiz said:
1 decade ago
In forward biased, diode is short circuit.
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