Electronic Devices - Semiconductor Diodes - Discussion
Discussion Forum : Semiconductor Diodes - General Questions (Q.No. 25)
25.
Calculate the temperature coefficient in %/° C of a 10-V nominal Zener diode at 25° C if the nominal voltage is 10.2 V at 100° C.
Discussion:
16 comments Page 1 of 2.
Anonymous said:
7 years ago
a = δV/δT.
Srinu yavarna said:
10 years ago
V1 = 10 V.
T1 = 25 c.
V2 = 10.2 V.
T2 = 100 c.
Then temperature coefficient is = [{(V2-V1)/V1}/(T2-T1)]*100.
= [(10.2-10/10)/(100-25)]*100.
= 0.0267 V.
T1 = 25 c.
V2 = 10.2 V.
T2 = 100 c.
Then temperature coefficient is = [{(V2-V1)/V1}/(T2-T1)]*100.
= [(10.2-10/10)/(100-25)]*100.
= 0.0267 V.
(1)
Neeraj mishra said:
1 decade ago
How it can be solved?
(1)
Shobhna raj said:
1 decade ago
V(T) = V(1+B(t2-t1)).
Where B is the coefficient.
Where B is the coefficient.
(2)
Berihum Molla said:
1 decade ago
Given:
vz = 10v.
Vo = 10.2v.
Tf = 100c.
Ti = 25c.
Download:
Tc = (vf-vi)/(tf-ti).
Tc = (10.2-10)/(100-25).
Tc = 0.2/75.
Tc = 0.0267.
vz = 10v.
Vo = 10.2v.
Tf = 100c.
Ti = 25c.
Download:
Tc = (vf-vi)/(tf-ti).
Tc = (10.2-10)/(100-25).
Tc = 0.2/75.
Tc = 0.0267.
(1)
Naina said:
1 decade ago
Proper formula please?
Sreeyush Sudhakaran said:
1 decade ago
Tempcoeff=(change in voltage/change in temp)x voltage at inital temperature
=(10.2-10)/(100-25) x 10
= 0.2/75 x10
=0.026666... = 0.0267
=(10.2-10)/(100-25) x 10
= 0.2/75 x10
=0.026666... = 0.0267
Rekha Garg said:
1 decade ago
Tcoeff=(change in voltage/change in temp)*voltage at inital temp
Here initial temp is 25degc & voltage is 10v
Here initial temp is 25degc & voltage is 10v
Selvamuthu said:
1 decade ago
Tcoeff = change in voltage/(change in temp * voltage at (TO))
TO initial temp ie 25 deg c in this problem.
TO initial temp ie 25 deg c in this problem.
Vijay said:
1 decade ago
Formula please.
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