Electronic Devices - Power Amplifiers - Discussion
Discussion Forum : Power Amplifiers - General Questions (Q.No. 54)
54.
Calculate the efficiency of a class B amplifier for a supply voltage of VCC = 20 V with peak output voltage of VL(p) = 18 V. Assume RL = 16
.
Discussion:
5 comments Page 1 of 1.
Komal said:
10 years ago
Please explain.
MR ad said:
10 years ago
How to solve this one?
Niviya said:
10 years ago
P(L) = Ic^2*RL/2 = V(L)*RL/2.
P(source) = Vcc*2Ic/pi.
=> Efficiency = PL/P source = pi/4*(VL/Vcc) = 0.9*pi/4.
P(source) = Vcc*2Ic/pi.
=> Efficiency = PL/P source = pi/4*(VL/Vcc) = 0.9*pi/4.
Rmr said:
9 years ago
How to solve this question?
Tin said:
7 years ago
Using Class B efficiency:
Formula:
%n = 78.54 (Vpout / Vcc).
Given
Vcc= 20Vp out.
VL= 18V,
RL= 16V,
%= 78.54( 18V/20V),
Efficiency= 70.69%.
Formula:
%n = 78.54 (Vpout / Vcc).
Given
Vcc= 20Vp out.
VL= 18V,
RL= 16V,
%= 78.54( 18V/20V),
Efficiency= 70.69%.
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