Electronic Devices - Power Amplifiers - Discussion
Discussion Forum : Power Amplifiers - General Questions (Q.No. 62)
62.
Determine VB1.
Discussion:
4 comments Page 1 of 1.
Mustapha Ali said:
4 years ago
Vbb =( 1.2/1.2+1.2)*20 10 voltage divider, the voltage across BE1= Vbb+Vbe which is 10 + 0.7 = 10.7v.
Lalaland said:
7 years ago
10.7 is correct.
Given the KVL and voltage division, we get V across resistors equals Vr = 9.3V.
Following the same KVL and you should know that Vb1 comprised of the two diodes and the V across the lowest 1.2k resistor.
That gives us 0.7 + 0.7 + 9.3 = 10.7V.
Given the KVL and voltage division, we get V across resistors equals Vr = 9.3V.
Following the same KVL and you should know that Vb1 comprised of the two diodes and the V across the lowest 1.2k resistor.
That gives us 0.7 + 0.7 + 9.3 = 10.7V.
Moira said:
8 years ago
So what is the real answer? please elaborate.
Suraj balaskar said:
8 years ago
According to me,
:
20-0.7-0.7=18.6.
Vb1=18.6/2=9.3.
Because R1 and R2 has same value.
So, the correct answer is 9.3.
:
20-0.7-0.7=18.6.
Vb1=18.6/2=9.3.
Because R1 and R2 has same value.
So, the correct answer is 9.3.
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