Electronic Devices - FET Amplifiers - Discussion
Discussion Forum : FET Amplifiers - General Questions (Q.No. 30)
30.
Referring to the transfer characteristics shown below, calculate gm at VGSQ = –1 V.
Discussion:
6 comments Page 1 of 1.
Gaboo said:
6 years ago
Idss=Id/(1-(vgs/vp))^2.
From the graph ID is equal 4mA when vgs is -1v,
Gm=(2Idss/vp)(1-vgs/vp),
Gm is approximately 3mS.
From the graph ID is equal 4mA when vgs is -1v,
Gm=(2Idss/vp)(1-vgs/vp),
Gm is approximately 3mS.
Vasudha said:
1 decade ago
From graph IDss = 8, Vp = -4.
gm = {2IDss/|Vp|}{1 - Vgs/Vp}.
= {2*8/|-4|}{1 - [-1/-4]}.
= (4}{3/4}.
= 3.
gm = {2IDss/|Vp|}{1 - Vgs/Vp}.
= {2*8/|-4|}{1 - [-1/-4]}.
= (4}{3/4}.
= 3.
Chad said:
3 years ago
I think Idq = 4 mA based on the graph.
VGsq = -1.
Then Idq= Idss(1-Vgsq/Vp)^2.
Get the value of Idss = 7.11mS.
VGsq = -1.
Then Idq= Idss(1-Vgsq/Vp)^2.
Get the value of Idss = 7.11mS.
Lurker said:
10 years ago
@Nyce.
Id = Idss/2 since Id is given in the graph Idss = id*2.
Id = Idss/2 since Id is given in the graph Idss = id*2.
Ryan said:
6 years ago
In the graph, Idss is equal to 8mA.
Nyce said:
1 decade ago
How did you get Idss = 8?
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