Electronic Devices - Diode Applications - Discussion
Discussion Forum : Diode Applications - General Questions (Q.No. 35)
35.
Calculate IL and IZ.
Discussion:
6 comments Page 1 of 1.
MANI said:
1 decade ago
Max current zener can with stand is only 3ma.
RIAZ said:
1 decade ago
Wastage rating of zener is 30mw so its in circuit to take Iz 4mA.
(1)
Sihle said:
1 decade ago
@Harshada I'm with you in that, how is it possible?
Titos said:
1 decade ago
1). Load current is simply found by 10v/5k = 2mA.
2). The output is regulated by zener @10v hence 6v is dropped by dropper resistor are which is 1K.
3). Total current is found by 6v/1k = 6mA.
4). Finally, Iz is 6mA-2mA = 4mA.
So the answer is option D.
2). The output is regulated by zener @10v hence 6v is dropped by dropper resistor are which is 1K.
3). Total current is found by 6v/1k = 6mA.
4). Finally, Iz is 6mA-2mA = 4mA.
So the answer is option D.
(2)
Harshada said:
1 decade ago
But the maximum rating for zener given is 30mW. Thus the max zener current it can handle is 3mA, the current of 4mA is greater than this. How can be the given ans correct?
(1)
Vijay_kr_daderwal said:
1 decade ago
Its a case of 'voltage regulator through zener diode'
VL will be the zener voltage i.e. 10v
Hence current through RL is V/R i.e. 10/5k =2mA
Current through R is (voltage difference across R)/resistance
i.e. (16-10)/1k =6mA
Hence current through zener diode= total current-Load current
i.e.6mA-2mA =4mA
VL will be the zener voltage i.e. 10v
Hence current through RL is V/R i.e. 10/5k =2mA
Current through R is (voltage difference across R)/resistance
i.e. (16-10)/1k =6mA
Hence current through zener diode= total current-Load current
i.e.6mA-2mA =4mA
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers