Electronic Devices - Diode Applications - Discussion
Discussion Forum : Diode Applications - General Questions (Q.No. 23)
23.
Determine the current level if E = 15 V and R = 3 k
.
. 
Discussion:
14 comments Page 1 of 2.
SANDEEP.BHEL DMR said:
1 decade ago
The min value of Si 0.7v
15-.7=14.3/3=4.76mA
15-.7=14.3/3=4.76mA
(1)
Niyas said:
1 decade ago
They have not specified here which diode is that. There for considering ideal diode the answer is 5ma only.
(1)
NIRANCHANA said:
1 decade ago
MY OPTION IS C.5mA BECAUSE E=IR(OHMS LAW)
THEREFORE I=E/R
=15V/3KOHM
=5mA
THEREFORE I=E/R
=15V/3KOHM
=5mA
Anishree said:
1 decade ago
I agree with niyas.
Yasmin said:
1 decade ago
What is the value of ideal diode ?
Venkateswarlu said:
1 decade ago
@Yasmin.
Voltage drop of Si is 0.7, Ge is 0.3 and Ideal diode is 0.
Voltage drop of Si is 0.7, Ge is 0.3 and Ideal diode is 0.
Saivam saini said:
1 decade ago
5mA is right answer because diode is consider ideal...
Shivam Saini
Shivam Saini
Ravikiranpokuri said:
1 decade ago
Here they are not mentioned the type of diode so we have to consider the Ideal case
So According to Ohms Law the Answer is C i.e. 5ma
So According to Ohms Law the Answer is C i.e. 5ma
RANJITH RAO said:
1 decade ago
As voltage is in series with diode, there is some voltage drop at diode. So 'v' at 'D'is 14.3, current in circuit is 4.8mA.
Srivani said:
9 years ago
@Niyas.
If it is not mentioned then we prefer silicon b/c it has low leakage current, more energy gap, and high resistivity.
If it is not mentioned then we prefer silicon b/c it has low leakage current, more energy gap, and high resistivity.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers