Electronic Devices - DC Biasing-FETs - Discussion
Discussion Forum : DC Biasing-FETs - General Questions (Q.No. 13)
13.
Calculate the value of RD.
2 k
3 k
3.5 k
4.13 k
Discussion:
4 comments Page 1 of 1.
Bitlblip said:
6 years ago
This could be KVL.
18V-3mA(Rd)-6V = 0.
Rd = 4k ~ 4.13k ohms.
18V-3mA(Rd)-6V = 0.
Rd = 4k ~ 4.13k ohms.
Mukul said:
9 years ago
i.e.
Vds = Vgs - Vth
=> 6 - 3 = 3 v.
Hence, Rd = (Vdd - Vds)/Ids.
= 3 Kohm.
Vds = Vgs - Vth
=> 6 - 3 = 3 v.
Hence, Rd = (Vdd - Vds)/Ids.
= 3 Kohm.
Sathya said:
1 decade ago
This is a amplifier, so saturation region.
In saturation region Vds = Vgs-Vt.
= 6-3 = 3v.
By kvl 18v = Id*Rd+Vds.
Therefore Rd = 5K ~4.13k.
Might be like this.
In saturation region Vds = Vgs-Vt.
= 6-3 = 3v.
By kvl 18v = Id*Rd+Vds.
Therefore Rd = 5K ~4.13k.
Might be like this.
Souvik said:
1 decade ago
Somebody please give the answer.
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