Electronic Devices - DC Biasing-FETs - Discussion
Discussion Forum : DC Biasing-FETs - General Questions (Q.No. 12)
12.
Calculate the value of RS. Assume VGSQ = −2V.
0 k
1.68 k
6.81 k
8.5 k
Discussion:
3 comments Page 1 of 1.
Bahkekekek said:
6 years ago
Vg = Vdd(R2/R2+R1)
= 18(47k/47k+91k)
Vg=5.449
KVL process
VDD-RdId-8=0
16-1.8kId-8=0
Id=4.44mA
Vgs=Vg-Vs
-2V= 5.449-Vs
Vs=7.449V
Vs=IdRs
7.449=4.44mARs
Rs=1676.19 ohms or 1.68komhs
= 18(47k/47k+91k)
Vg=5.449
KVL process
VDD-RdId-8=0
16-1.8kId-8=0
Id=4.44mA
Vgs=Vg-Vs
-2V= 5.449-Vs
Vs=7.449V
Vs=IdRs
7.449=4.44mARs
Rs=1676.19 ohms or 1.68komhs
Suraj balaskar said:
8 years ago
Vg = (16 * 47)/(91+47),
Vgs = Vg-Vs.
Id = (16-8)/(1.8*10^3),
Vs = Id * Rs.
Vgs = Vg-Vs.
Id = (16-8)/(1.8*10^3),
Vs = Id * Rs.
Kimchong said:
1 decade ago
What is Vgsq ?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers