Electronic Devices - DC Biasing-BJTs - Discussion
Discussion Forum : DC Biasing-BJTs - General Questions (Q.No. 19)
19.
Determine ICQ at a temperature of 175º C if ICQ = 2 mA at 25º C for RB / RE = 20 due to the S(
) stability factor.
) stability factor.Discussion:
5 comments Page 1 of 1.
Anakin said:
7 months ago
The formula is;
S= (Ic1 (1+(RB/RE))) / (B1 (B2+(RB/RE))).
Then use the formula S= (change in Ic)/(change in B).
S= (Ic1 (1+(RB/RE))) / (B1 (B2+(RB/RE))).
Then use the formula S= (change in Ic)/(change in B).
PAULO VICO said:
6 years ago
Correction! :
S(B) =(1+RB/RE)/(β(1)(1 +β(2) + RB/RE)).
S(B) =(1+RB/RE)/(β(1)(1 +β(2) + RB/RE)).
Danabacco said:
6 years ago
The formula of Stability factor is:
S(B) = δ(Ic)/δ(β).
= ( Ic(1)(1+RB/RE) )/(β(1)(1 +β(2) + RB/RE)).
Ic (1) = 2mA.
To know Beta, see the table of Variation of Silicon Transistor Parameters with Temperature.
175 degree = 120β.
25 degree = 50β.
Apply values in the formula, then we get the answer.
S(B) = δ(Ic)/δ(β).
= ( Ic(1)(1+RB/RE) )/(β(1)(1 +β(2) + RB/RE)).
Ic (1) = 2mA.
To know Beta, see the table of Variation of Silicon Transistor Parameters with Temperature.
175 degree = 120β.
25 degree = 50β.
Apply values in the formula, then we get the answer.
Carlo said:
6 years ago
Please explain it.
Mark said:
6 years ago
Can anyone explain me?
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