Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 1)
1.
What kVA rating is required for a transformer that must handle a maximum load current of 8 A with a secondary voltage of 2 kV?
4 kVA
0.25 kVA
16 kVA
8 kVA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
121 comments Page 6 of 13.

Subham bahirlman said:   1 decade ago
Why using this formula?

Raja said:   1 decade ago
Kva in primary = kva in secondary.

Maximum load = 8A = secondary current.

Secondary voltage = 2KV.

.'.KVA = Secondary current * Secondary voltage.
= 8*2*1000.
= 16Kva.

Charu said:   1 decade ago
In transformer copper loss is depends on current ( I^2 R ) and core loss is depends on voltage, so only the rating of transformer is expressed in KVA.

So KVA = secondary current x secondary voltage.
KVA = 8 x 2.
KVA = 16 KVA.

Rahul kumar said:   1 decade ago
The given power is reactive power so how can we say it is a load,

Because reactive power did not require for a load but it work only with inductor and capacitor.

Mohan said:   1 decade ago
When transformer output rating in MVA then how can get the answers?

POOJA GUPTA said:   1 decade ago
WE KNOW THAT,

POWER ON LOAD SIDE,

SO,

P = V2*I2.

P = 8A*2KV = 16 KVA.

Chiranjeevi said:   1 decade ago
Transformer rating is in KVA(Apparent Power).

Apparent power = V*I = 2KV*8A = 16 KVA.

Mahantesh.GM said:   1 decade ago
Transformer output power rating in KVA.

KVA = V X I = 2X8 = 16.

Anshuman said:   1 decade ago
Power = Voltage*Current.

Power on load side = V2*I2.

Here P = 2kv*8A.

=16kvA.

Ramesh yadav said:   1 decade ago
What will happen if t/f is made from magnet in place of iron?


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