Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 16)
16.
A certain amplifier has 600 
internal resistance looking from its output. In order to provide maximum power to a 4 speaker, what turns ratio must be used in the coupling transformer?
internal resistance looking from its output. In order to provide maximum power to a 4 speaker, what turns ratio must be used in the coupling transformer?Discussion:
19 comments Page 1 of 2.
Nishant said:
7 years ago
I think it is the wrong answers.
Because, turn ratio of the transformer is V1/V2, N1/N2, E1/E2, and I2/I1.
So, transformer transfer constant power.
V1 * I1 = V2 * I2.
V1 * V1/R1 = V2 * V2/ R2.
V1 ^2 / R1 = V2 ^2 / R2.
V1^2/V2^2 = R1/R2,
V1/V2 = Sq. Rt. Of (R1/R2).
We know that T.R:-K = V1/V2
So, K = 600/4 =12.24.
Because, turn ratio of the transformer is V1/V2, N1/N2, E1/E2, and I2/I1.
So, transformer transfer constant power.
V1 * I1 = V2 * I2.
V1 * V1/R1 = V2 * V2/ R2.
V1 ^2 / R1 = V2 ^2 / R2.
V1^2/V2^2 = R1/R2,
V1/V2 = Sq. Rt. Of (R1/R2).
We know that T.R:-K = V1/V2
So, K = 600/4 =12.24.
(1)
Rajesh said:
9 years ago
Transformer transfer constant power.
V1 * I1 = V2 * I2.
V1 * V1/r1 = V2 * V2/ r2.
V1 ^2 / r1 = V2 ^2 / r2.
Sq of (V2/V1) = r2 / r1.
(V2 / V1) = sq rt of (r2 / r1).
k = sq rt of (4 / 600).
k = 0.081.
V1 * I1 = V2 * I2.
V1 * V1/r1 = V2 * V2/ r2.
V1 ^2 / r1 = V2 ^2 / r2.
Sq of (V2/V1) = r2 / r1.
(V2 / V1) = sq rt of (r2 / r1).
k = sq rt of (4 / 600).
k = 0.081.
Akash.bhure said:
1 decade ago
Internal resistance(R1)=600 ohms.
Output speaker(R2)=4 ohms.
R1 = R2/K^2.
600 = 4/K^2.
K^2 = 4/600 = 0.0066.
K = sqrt(0.0066) = 0.081.
Output speaker(R2)=4 ohms.
R1 = R2/K^2.
600 = 4/K^2.
K^2 = 4/600 = 0.0066.
K = sqrt(0.0066) = 0.081.
E.sravani said:
1 decade ago
Power = i^2r.
Input power = i1^2r1 = i1^2(600).
Output power = i2^2r2 = i2^2(4).
P(in) = P(out).
i1^2(600) = i2^2(4).
K^2 = (4/600) {(i1/i2)^2 = k^2}.
K = 0.08.
Input power = i1^2r1 = i1^2(600).
Output power = i2^2r2 = i2^2(4).
P(in) = P(out).
i1^2(600) = i2^2(4).
K^2 = (4/600) {(i1/i2)^2 = k^2}.
K = 0.08.
Mohsin Yaqoob said:
9 years ago
Simple!
Turn ratio = sqr (load impedance/source impedance).
Here load imp is speaker ie, 4ohm and source is 600ohm.
so, sqr (4/600) = 0.08.
Turn ratio = sqr (load impedance/source impedance).
Here load imp is speaker ie, 4ohm and source is 600ohm.
so, sqr (4/600) = 0.08.
(3)
Saritha said:
1 decade ago
Here,
Load resistance(destination)=4 ohms
Source resistance=600 ohms
k=(r2/r1)^0.5
=(4/600)^0.5
=0.0816
k=0.0816 ohms
Load resistance(destination)=4 ohms
Source resistance=600 ohms
k=(r2/r1)^0.5
=(4/600)^0.5
=0.0816
k=0.0816 ohms
DIN said:
9 years ago
As per my knowledge.
Turns ratio = Np/Ns not Ns/Np.
Is/Ip is the turns ratio.
So, I think it is the wrong answers.
Turns ratio = Np/Ns not Ns/Np.
Is/Ip is the turns ratio.
So, I think it is the wrong answers.
(1)
Ajit said:
9 years ago
According to me, it's the wrong answer.
The turns ratio = (source impedence/load impedence)^0.5.
Answer = 12.24.
The turns ratio = (source impedence/load impedence)^0.5.
Answer = 12.24.
(1)
Amani naidu said:
9 years ago
No, turns ratio is n1/n2. Transformation ratio is n2/n1.
You are right @Din.
You are right @Din.
Siri said:
1 decade ago
@Saritha.
Transformation ratio is unit less quantity.
Not measured in ohms.
Transformation ratio is unit less quantity.
Not measured in ohms.
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