Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 16)
16.
A certain amplifier has 600 
internal resistance looking from its output. In order to provide maximum power to a 4 speaker, what turns ratio must be used in the coupling transformer?
internal resistance looking from its output. In order to provide maximum power to a 4 speaker, what turns ratio must be used in the coupling transformer?Discussion:
19 comments Page 2 of 2.
Sahal said:
9 years ago
How can we solve the sqrt without a calculator? any one please suggest me.
Manish said:
1 decade ago
V2/I2 = 4.
V1/I1 = 600.
V2xI1/V1xI2 = 4/600.
N2 = 4/600N1 = 0.08.
V1/I1 = 600.
V2xI1/V1xI2 = 4/600.
N2 = 4/600N1 = 0.08.
ShaijuTS said:
1 decade ago
Pow((Ns/Np),2) = Zs/Zp
ie. pow(k,2) = 4/600
k=sqrt(4/600)
k=0.08
ie. pow(k,2) = 4/600
k=sqrt(4/600)
k=0.08
Ashim said:
1 decade ago
Turns ratio K = N2/N1= sqrt (R2/R1) = sqrt (4/600) = 0.08.
Love said:
1 decade ago
But it is asked to determine turn ratio = 1/K.
Mouneshwara said:
9 years ago
@Din.
Turns ratio ns/np is the correct one.
Turns ratio ns/np is the correct one.
Er MAHESH said:
9 years ago
Thanks a lot @RAJESH & @Sravani.
(1)
Rakesh alliwar said:
9 years ago
Yes, 0.08 is the correct answer.
Suhail said:
8 years ago
Here, K^2=Z1÷Z2.
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