Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 8)
8.
The mutual inductance when k = 0.65, L1 = 2 
H, and L2 = 5 H is
H, and L2 = 5 H is2 mH
2 H
H4 H
H8 H
HDiscussion:
39 comments Page 2 of 4.
Santosh said:
1 decade ago
M=k*sqrt(L1*L2) this is according to the coupling coefficent
Nidhi said:
1 decade ago
Coefficient of coupling k=M/(sqrt(L1*L2))
Therefore M=K*[sqrt(L1*L2)]
Therefore M=K*[sqrt(L1*L2)]
S.ANJINEYULU NAIK said:
1 decade ago
Mutual inductance, M=k*sqrt(L1*L2)
=0.65*3.162
=2
=0.65*3.162
=2
Lakshmi Nagesh said:
1 decade ago
formula is perfect
M = K(sqrt(L1*L2))
M= 0.65(sqrt(2*10^-6 * 5* 10^-6))
= 0.65(sqrt(2*5))(sqrt(10^-12))
= 0.65(3.162)(10^-6)
= 2micro Henry.
M = K(sqrt(L1*L2))
M= 0.65(sqrt(2*10^-6 * 5* 10^-6))
= 0.65(sqrt(2*5))(sqrt(10^-12))
= 0.65(3.162)(10^-6)
= 2micro Henry.
Harika Gadde said:
1 decade ago
Formula is
Coupling Coefficient K=M/(sqrt(L1*L2))
Coupling Coefficient K=M/(sqrt(L1*L2))
Panduu said:
1 decade ago
k=coupling coefficient.
m=mutual inductance.
L1=inductance1.
L2=inductance2.
k=m/SQUARE ROOT OF(L1*L2).
m=mutual inductance.
L1=inductance1.
L2=inductance2.
k=m/SQUARE ROOT OF(L1*L2).
Suyog Shrivastava said:
1 decade ago
According to coefficient of coupling,
K = M/sqrt(L1*L2).
where ,
M = K*sqrt(L1*L2).
M = 0.65*sqrt(5*10).
M = 0.65*3.15.
M = 2.
K = M/sqrt(L1*L2).
where ,
M = K*sqrt(L1*L2).
M = 0.65*sqrt(5*10).
M = 0.65*3.15.
M = 2.
Shyama Sundar jena said:
1 decade ago
M = K*^1/2(L1*L2).
So M = 0.65*3.15.
= approx 2micro H
So M = 0.65*3.15.
= approx 2micro H
V N Bhoyar said:
1 decade ago
M = k sq. root of L1*L2.
Rajiv Nautiyal said:
1 decade ago
Is it 2 micro H or 2 milli H?
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