Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 8)
8.
The mutual inductance when k = 0.65, L1 = 2 
H, and L2 = 5 H is
H, and L2 = 5 H is2 mH
2 H
H4 H
H8 H
HDiscussion:
39 comments Page 1 of 4.
Lakshmi Nagesh said:
1 decade ago
formula is perfect
M = K(sqrt(L1*L2))
M= 0.65(sqrt(2*10^-6 * 5* 10^-6))
= 0.65(sqrt(2*5))(sqrt(10^-12))
= 0.65(3.162)(10^-6)
= 2micro Henry.
M = K(sqrt(L1*L2))
M= 0.65(sqrt(2*10^-6 * 5* 10^-6))
= 0.65(sqrt(2*5))(sqrt(10^-12))
= 0.65(3.162)(10^-6)
= 2micro Henry.
Ekalabya meher said:
1 year ago
According to the coefficient of coupling,
K = M/√(L1 * L2).
where,
M = K*√(L1*L2).
M = 0.65*√(5*10).
M = 0.65*3.15.
M = 2.
K = M/√(L1 * L2).
where,
M = K*√(L1*L2).
M = 0.65*√(5*10).
M = 0.65*3.15.
M = 2.
(4)
Suyog Shrivastava said:
1 decade ago
According to coefficient of coupling,
K = M/sqrt(L1*L2).
where ,
M = K*sqrt(L1*L2).
M = 0.65*sqrt(5*10).
M = 0.65*3.15.
M = 2.
K = M/sqrt(L1*L2).
where ,
M = K*sqrt(L1*L2).
M = 0.65*sqrt(5*10).
M = 0.65*3.15.
M = 2.
Shenbalaxmi said:
8 years ago
K-Coupling factor
L1,L2-Self inductance
M-Mutual inductance
M = K * sqrt(L1 * L2),
M = 0.65 * (2x10^-6x5x10^-6).
M = 2microHenry.
L1,L2-Self inductance
M-Mutual inductance
M = K * sqrt(L1 * L2),
M = 0.65 * (2x10^-6x5x10^-6).
M = 2microHenry.
(6)
Siri said:
1 decade ago
K=M/sqrt(L1*L2)...............(According to coefficient of coupling)
i.e M=K*sqrt(L1*L2)
=.65*sqrt(5*10)
=.65*3.15
=2.055
Appox=2
i.e M=K*sqrt(L1*L2)
=.65*sqrt(5*10)
=.65*3.15
=2.055
Appox=2
Panduu said:
1 decade ago
k=coupling coefficient.
m=mutual inductance.
L1=inductance1.
L2=inductance2.
k=m/SQUARE ROOT OF(L1*L2).
m=mutual inductance.
L1=inductance1.
L2=inductance2.
k=m/SQUARE ROOT OF(L1*L2).
S.ANJINEYULU NAIK said:
1 decade ago
Mutual inductance, M=k*sqrt(L1*L2)
=0.65*3.162
=2
=0.65*3.162
=2
P venkateswara reddy said:
10 years ago
As we know that M = K (L1*L2)^(1/2).
M = 0.65*(2*5*10^-6*10^-6)^(1/2) = 2 uH.
M = 0.65*(2*5*10^-6*10^-6)^(1/2) = 2 uH.
Nidhi said:
1 decade ago
Coefficient of coupling k=M/(sqrt(L1*L2))
Therefore M=K*[sqrt(L1*L2)]
Therefore M=K*[sqrt(L1*L2)]
Waseem guru said:
1 decade ago
M = Mutual Inductance
M = k*(L1*L2)^1/2
M = 0.65(10)^1/2
M = 2uH
M = k*(L1*L2)^1/2
M = 0.65(10)^1/2
M = 2uH
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