Electrical Engineering - Transformers - Discussion

Discussion :: Transformers - General Questions (Q.No.8)

8. 

The mutual inductance when k = 0.65, L1 = 2 H, and L2 = 5 H is

[A]. 2 mH
[B]. 2 H
[C]. 4 H
[D]. 8 H

Answer: Option B

Explanation:

No answer description available for this question.

Waseem Guru said: (Dec 13, 2010)  
M = Mutual Inductance
M = k*(L1*L2)^1/2
M = 0.65(10)^1/2
M = 2uH

Naresh said: (Aug 11, 2011)  
I did not understand the formula clearly.

Archu said: (Aug 14, 2011)  
k=M/(L1*L2)^1/2

Yousuf said: (Sep 29, 2011)  
This formula is correct. It is related to coupling coefficient.

Kondalu said: (Nov 5, 2011)  
It is correct.

Ankit said: (Mar 20, 2012)  
k=M/(L1*L2)^1/2

Vijay Balu Raskar said: (Mar 25, 2012)  
Formula is correct.

Ganesh said: (Apr 13, 2012)  
M=MUTUAL Inductance
M=K(L1*L2)^1/2

Balagangadhara said: (Apr 16, 2012)  
I did not understand the formula used to data clearly.

Siri said: (May 24, 2012)  
K=M/sqrt(L1*L2)...............(According to coefficient of coupling)
i.e M=K*sqrt(L1*L2)
=.65*sqrt(5*10)
=.65*3.15
=2.055
Appox=2

Santosh said: (Jun 8, 2012)  
M=k*sqrt(L1*L2) this is according to the coupling coefficent

Nidhi said: (Jun 10, 2012)  
Coefficient of coupling k=M/(sqrt(L1*L2))
Therefore M=K*[sqrt(L1*L2)]

S.Anjineyulu Naik said: (Oct 1, 2012)  
Mutual inductance, M=k*sqrt(L1*L2)
=0.65*3.162
=2

Lakshmi Nagesh said: (Nov 14, 2012)  
formula is perfect
M = K(sqrt(L1*L2))
M= 0.65(sqrt(2*10^-6 * 5* 10^-6))
= 0.65(sqrt(2*5))(sqrt(10^-12))
= 0.65(3.162)(10^-6)
= 2micro Henry.

Harika Gadde said: (Dec 21, 2012)  
Formula is
Coupling Coefficient K=M/(sqrt(L1*L2))

Panduu said: (Feb 10, 2013)  
k=coupling coefficient.
m=mutual inductance.
L1=inductance1.
L2=inductance2.

k=m/SQUARE ROOT OF(L1*L2).

Suyog Shrivastava said: (Jun 11, 2013)  
According to coefficient of coupling,

K = M/sqrt(L1*L2).

where ,

M = K*sqrt(L1*L2).

M = 0.65*sqrt(5*10).

M = 0.65*3.15.

M = 2.

Shyama Sundar Jena said: (Aug 29, 2013)  
M = K*^1/2(L1*L2).

So M = 0.65*3.15.

= approx 2micro H

V N Bhoyar said: (Jul 20, 2014)  
M = k sq. root of L1*L2.

Rajiv Nautiyal said: (Dec 18, 2014)  
Is it 2 micro H or 2 milli H?

Pramod Rps said: (Feb 6, 2015)  
Its micro obviously.

Priyanka said: (Jun 18, 2015)  
L2=5, not 10 hows write 10.

P Venkateswara Reddy said: (Aug 25, 2015)  
As we know that M = K (L1*L2)^(1/2).

M = 0.65*(2*5*10^-6*10^-6)^(1/2) = 2 uH.

Nakul said: (Dec 11, 2015)  
I can't understand this example, please explain.

Sravanthi said: (Apr 20, 2016)  
The correct formulae are k=M/(L1*L2)^1/2.

Shekar said: (Aug 30, 2016)  
M = k * (L1 L2)^1/2 .

Jittu said: (Dec 25, 2016)  
Good answer. Thanks you all.

Manjunath Ukkali said: (Dec 29, 2016)  
Not getting it. Please help me.

P. Rajesh said: (Mar 11, 2017)  
How to apply 5*10 in sum?

Shenbalaxmi said: (Apr 11, 2017)  
K-Coupling factor
L1,L2-Self inductance
M-Mutual inductance

M = K * sqrt(L1 * L2),
M = 0.65 * (2x10^-6x5x10^-6).
M = 2microHenry.

Juber Alam said: (Apr 17, 2017)  
The co-efficient of coupling K=M/(SqrtL1*L2).

Anil said: (Apr 29, 2017)  
Mutual inductance: coefficient of coupling * √ inductance.

Kanyasri said: (Jun 7, 2017)  
M = K(L1 * L2)^1/2,
M = 0.65(10)^1/2,
M = 2UH.

Kanyasri said: (Jun 7, 2017)  
Formula M^2 = (L1 * L2).

Abhishek said: (Aug 29, 2017)  
It is 2M/L1*L2.

Muhammed said: (Aug 8, 2018)  
Thank you for the explanation.

Avnish Kumar said: (Oct 3, 2018)  
Nice, Thanks for giving this section.

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