Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 8)
8.
The mutual inductance when k = 0.65, L1 = 2
H, and L2 = 5
H is


Discussion:
39 comments Page 1 of 4.
Ekalabya meher said:
1 year ago
According to the coefficient of coupling,
K = M/√(L1 * L2).
where,
M = K*√(L1*L2).
M = 0.65*√(5*10).
M = 0.65*3.15.
M = 2.
K = M/√(L1 * L2).
where,
M = K*√(L1*L2).
M = 0.65*√(5*10).
M = 0.65*3.15.
M = 2.
(4)
HUBERT NAHIMANA said:
2 years ago
M = k * √L1*L2.
(1)
Avnish kumar said:
7 years ago
Nice, Thanks for giving this section.
(2)
Muhammed said:
7 years ago
Thank you for the explanation.
(1)
Abhishek said:
8 years ago
It is 2M/L1*L2.
KANYASRI said:
8 years ago
Formula M^2 = (L1 * L2).
(1)
Kanyasri said:
8 years ago
M = K(L1 * L2)^1/2,
M = 0.65(10)^1/2,
M = 2UH.
M = 0.65(10)^1/2,
M = 2UH.
(1)
Anil said:
8 years ago
Mutual inductance: coefficient of coupling * √ inductance.
(3)
JUBER ALAM said:
8 years ago
The co-efficient of coupling K=M/(SqrtL1*L2).
Shenbalaxmi said:
8 years ago
K-Coupling factor
L1,L2-Self inductance
M-Mutual inductance
M = K * sqrt(L1 * L2),
M = 0.65 * (2x10^-6x5x10^-6).
M = 2microHenry.
L1,L2-Self inductance
M-Mutual inductance
M = K * sqrt(L1 * L2),
M = 0.65 * (2x10^-6x5x10^-6).
M = 2microHenry.
(6)
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