# Electrical Engineering - Transformers - Discussion

### Discussion :: Transformers - General Questions (Q.No.8)

8.

The mutual inductance when k = 0.65, L1 = 2 H, and L2 = 5 H is

 [A]. 2 mH [B]. 2 H [C]. 4 H [D]. 8 H

Explanation:

No answer description available for this question.

 Waseem Guru said: (Dec 13, 2010) M = Mutual Inductance M = k*(L1*L2)^1/2 M = 0.65(10)^1/2 M = 2uH

 Naresh said: (Aug 11, 2011) I did not understand the formula clearly.

 Archu said: (Aug 14, 2011) k=M/(L1*L2)^1/2

 Yousuf said: (Sep 29, 2011) This formula is correct. It is related to coupling coefficient.

 Kondalu said: (Nov 5, 2011) It is correct.

 Ankit said: (Mar 20, 2012) k=M/(L1*L2)^1/2

 Vijay Balu Raskar said: (Mar 25, 2012) Formula is correct.

 Ganesh said: (Apr 13, 2012) M=MUTUAL Inductance M=K(L1*L2)^1/2

 Balagangadhara said: (Apr 16, 2012) I did not understand the formula used to data clearly.

 Siri said: (May 24, 2012) K=M/sqrt(L1*L2)...............(According to coefficient of coupling) i.e M=K*sqrt(L1*L2) =.65*sqrt(5*10) =.65*3.15 =2.055 Appox=2

 Santosh said: (Jun 8, 2012) M=k*sqrt(L1*L2) this is according to the coupling coefficent

 Nidhi said: (Jun 10, 2012) Coefficient of coupling k=M/(sqrt(L1*L2)) Therefore M=K*[sqrt(L1*L2)]

 S.Anjineyulu Naik said: (Oct 1, 2012) Mutual inductance, M=k*sqrt(L1*L2) =0.65*3.162 =2

 Lakshmi Nagesh said: (Nov 14, 2012) formula is perfect M = K(sqrt(L1*L2)) M= 0.65(sqrt(2*10^-6 * 5* 10^-6)) = 0.65(sqrt(2*5))(sqrt(10^-12)) = 0.65(3.162)(10^-6) = 2micro Henry.

 Harika Gadde said: (Dec 21, 2012) Formula is Coupling Coefficient K=M/(sqrt(L1*L2))

 Panduu said: (Feb 10, 2013) k=coupling coefficient. m=mutual inductance. L1=inductance1. L2=inductance2. k=m/SQUARE ROOT OF(L1*L2).

 Suyog Shrivastava said: (Jun 11, 2013) According to coefficient of coupling, K = M/sqrt(L1*L2). where , M = K*sqrt(L1*L2). M = 0.65*sqrt(5*10). M = 0.65*3.15. M = 2.

 Shyama Sundar Jena said: (Aug 29, 2013) M = K*^1/2(L1*L2). So M = 0.65*3.15. = approx 2micro H

 V N Bhoyar said: (Jul 20, 2014) M = k sq. root of L1*L2.

 Rajiv Nautiyal said: (Dec 18, 2014) Is it 2 micro H or 2 milli H?

 Pramod Rps said: (Feb 6, 2015) Its micro obviously.

 Priyanka said: (Jun 18, 2015) L2=5, not 10 hows write 10.

 P Venkateswara Reddy said: (Aug 25, 2015) As we know that M = K (L1*L2)^(1/2). M = 0.65*(2*5*10^-6*10^-6)^(1/2) = 2 uH.

 Nakul said: (Dec 11, 2015) I can't understand this example, please explain.

 Sravanthi said: (Apr 20, 2016) The correct formulae are k=M/(L1*L2)^1/2.

 Shekar said: (Aug 30, 2016) M = k * (L1 L2)^1/2 .

 Jittu said: (Dec 25, 2016) Good answer. Thanks you all.

 P. Rajesh said: (Mar 11, 2017) How to apply 5*10 in sum?

 Shenbalaxmi said: (Apr 11, 2017) K-Coupling factor L1,L2-Self inductance M-Mutual inductance M = K * sqrt(L1 * L2), M = 0.65 * (2x10^-6x5x10^-6). M = 2microHenry.

 Juber Alam said: (Apr 17, 2017) The co-efficient of coupling K=M/(SqrtL1*L2).

 Anil said: (Apr 29, 2017) Mutual inductance: coefficient of coupling * √ inductance.

 Kanyasri said: (Jun 7, 2017) M = K(L1 * L2)^1/2, M = 0.65(10)^1/2, M = 2UH.

 Kanyasri said: (Jun 7, 2017) Formula M^2 = (L1 * L2).

 Abhishek said: (Aug 29, 2017) It is 2M/L1*L2.

 Muhammed said: (Aug 8, 2018) Thank you for the explanation.

 Avnish Kumar said: (Oct 3, 2018) Nice, Thanks for giving this section.