Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 2)
2.
The turns ratio required to match an 80 
source to a 320 load is
source to a 320 load isDiscussion:
101 comments Page 6 of 11.
Engr. Mamoona Akbar said:
1 decade ago
Turn ratio*2 = load impedance/source impedance.
Ranjeet singh said:
1 decade ago
v2/v1 = i1/i2.
= v1/r1*r2/v2.
(v2/v1)^2 = r2/r1.
(k)^2 = r2/r1.
k^2 = 320/80.
k^2 = 4 .
k = 2.
= v1/r1*r2/v2.
(v2/v1)^2 = r2/r1.
(k)^2 = r2/r1.
k^2 = 320/80.
k^2 = 4 .
k = 2.
Ramm said:
1 decade ago
Transformer rating is KVA, because iron&Cu losses depending upon the voltage and current only. Then not depending in the pf so its calls kva only.
Gursewak Singh said:
1 decade ago
Turns Ratio = sqrt(r2/r1).
= sqrt (320/80).
= sqrt (4).
= 2.
= sqrt (320/80).
= sqrt (4).
= 2.
Prakash said:
1 decade ago
What is turns ratio? please explain.
Arun Kumar Raju C said:
1 decade ago
The turns ratio of a transformer is defined as the number of turns on its secondary divided by the number of turns on its primary.
Akash.bhure said:
1 decade ago
Source resistance(R1) = 80 ohms.
Load resistance(R2) = 320 ohms.
R1 = R2/K^2.
80 = 320/K^2.
K^2 = 320/80 = 4.
K = sqrt(4) = 2.
Load resistance(R2) = 320 ohms.
R1 = R2/K^2.
80 = 320/K^2.
K^2 = 320/80 = 4.
K = sqrt(4) = 2.
Saranya said:
1 decade ago
Single phase transformer 50hz 200 kva 11kv/230v test results: no load test: input = 1600watts short circuit test : 2600 watts calculate all day efficiency duty cycle 160kw 0.8 pf 8 hr 100kw unity pf 6hr remaining hrs no load.
Krishnakant said:
1 decade ago
Numerical solution of single and three phase transformer.
Krishna said:
1 decade ago
What is the relation the number of turns and the resistance?
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