Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 2)
2.
The turns ratio required to match an 80
source to a 320
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Discussion:
101 comments Page 4 of 11.
Amjad moawia said:
9 years ago
No! @Hanumantha Hk.
The correct law is : vs/sp = NS/NP = IP/IS.
Please, revise once again.
The correct law is : vs/sp = NS/NP = IP/IS.
Please, revise once again.
Hanumantha HK said:
9 years ago
Above all guys discussed ok but there is a mistake in that !
Turns ratio(n) = N1/N2 =V1/V2 = I2/I1.
Same Transformer ratio is (K) = 1/n.
Means V2/V1 = N2/N1 = I1/I2 = K.
The question is Turns Ratio ?
V1*I1=V2*I2.
(v1)^2/R1= (V2)^2/R2.
So (V1/V2)^2=R1/R2.
Turns ratio n = (N1/N2)^2=R1/R2=80/320=1/4.
When we make sqrt it will come = 1/2.
What you guys are saying the above solution ?
Turns ratio(n) = N1/N2 =V1/V2 = I2/I1.
Same Transformer ratio is (K) = 1/n.
Means V2/V1 = N2/N1 = I1/I2 = K.
The question is Turns Ratio ?
V1*I1=V2*I2.
(v1)^2/R1= (V2)^2/R2.
So (V1/V2)^2=R1/R2.
Turns ratio n = (N1/N2)^2=R1/R2=80/320=1/4.
When we make sqrt it will come = 1/2.
What you guys are saying the above solution ?
Chandrashekar said:
10 years ago
320 = n^2*80.
n^2 = 320/80 = 4.
n = 2.
n^2 = 320/80 = 4.
n = 2.
GAUTAM said:
10 years ago
Clearly given in question that:
Primary or source resistance R1 = 80 ohm.
Secondary resistance R2 = 320.
We know that:
Transformation ratio k = N1/N2 = V1/V2 = R2/R1 = I2/I1.
SO K = 320/80 = 4 is correct answer.
Primary or source resistance R1 = 80 ohm.
Secondary resistance R2 = 320.
We know that:
Transformation ratio k = N1/N2 = V1/V2 = R2/R1 = I2/I1.
SO K = 320/80 = 4 is correct answer.
Reshma said:
1 decade ago
I m not satisfy this answer.
Turn ratio = E1/E2 =V1/V2 =N1/N2=1/k.
Turn ratio = E1/E2 =V1/V2 =N1/N2=1/k.
Pal said:
1 decade ago
N(s)/N(p) = E(S)/E(p)-1.
I(p) N(p) = I(s) N(p).
E(P) N(P) / R(P) = E(S) N(S)/R(S)-2.
From 1 and 2.
Sq (N(S)/N(P)) = R(s)/R(p).
I(p) N(p) = I(s) N(p).
E(P) N(P) / R(P) = E(S) N(S)/R(S)-2.
From 1 and 2.
Sq (N(S)/N(P)) = R(s)/R(p).
Rangaswamy M.D said:
1 decade ago
v2/v1 = i1/i2.
= v1/r1*r2/v2.
(v2/v1)^2 = r2/r1.
(k)^2 = r2/r1.
k^2 = 320/80.
k^2 = 4 .
k = 2.
= v1/r1*r2/v2.
(v2/v1)^2 = r2/r1.
(k)^2 = r2/r1.
k^2 = 320/80.
k^2 = 4 .
k = 2.
Krishnakumar said:
1 decade ago
During current loss test (short circuit) we had applied rated current of the transformer. Transformer reaches its rated current at some voltage. It is very low current loss only depend on voltage. So it is negligible.
Saheb said:
1 decade ago
R(hv) = K^2*R(lv).
[v2/v1 = k,i2*r2/i1*r1 = k, R(hv)/R(lv) = k^2; k = 2; r2/r1 = k^2].
[v2/v1 = k,i2*r2/i1*r1 = k, R(hv)/R(lv) = k^2; k = 2; r2/r1 = k^2].
RAJESH KANNA said:
1 decade ago
What is the meaning of unbalancing?
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