Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 4)
4.
If a transformer has 50 turns in the primary winding and 10 turns in the secondary winding, what is the reflective resistance if the secondary load resistance is 250 
?
?250
25
6,250
62,500
Discussion:
46 comments Page 5 of 5.
Pinnapareddy .sandhya lakshmi said:
1 decade ago
r1=r2/k^2
k=n2/n1=10/50=1/5
r2=250
r1=250/(1/5)^2=6250
r1=6250
k=n2/n1=10/50=1/5
r2=250
r1=250/(1/5)^2=6250
r1=6250
Siddu said:
1 decade ago
Turns ratio will proportional to square of load then square of resistance in sec/pri 2n square.
Chintan said:
1 decade ago
N1=50 , N2=10
Turn ratio K=N2/N1=10/50
K=1/5=0.2
now,R2/R1=K^2
R1=R2/K^2
=250/0.2^2
R1=6250 ohms.
Turn ratio K=N2/N1=10/50
K=1/5=0.2
now,R2/R1=K^2
R1=R2/K^2
=250/0.2^2
R1=6250 ohms.
Prakash. D. said:
1 decade ago
Turns ratio K= n1/n2= 50/10
K=5,
w.k.t..., R1/R2=K^2
R1=250*25
R1=6250 ohms.
K=5,
w.k.t..., R1/R2=K^2
R1=250*25
R1=6250 ohms.
HJHGJK said:
1 decade ago
K=N2/N1
N1=50
N2=10
K=(10/50)=1/5
SECONDARY TO PRIMARY R/K^2
SO 250/(1/5)^2=250*25=6250 OHMS
N1=50
N2=10
K=(10/50)=1/5
SECONDARY TO PRIMARY R/K^2
SO 250/(1/5)^2=250*25=6250 OHMS
Bhagyashree said:
1 decade ago
R2=250
k=n1/n2=50/10
R1=R2*k^2
=250*(2500/100)
R1=6250ohm
k=n1/n2=50/10
R1=R2*k^2
=250*(2500/100)
R1=6250ohm
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