Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 4)
4.
If a transformer has 50 turns in the primary winding and 10 turns in the secondary winding, what is the reflective resistance if the secondary load resistance is 250 
?
?250
25
6,250
62,500
Discussion:
46 comments Page 4 of 5.
Kuldeep Bisht said:
1 decade ago
Primary resistence R'=R2/(K)2
here k=N2/N1=10/50=0.2
hence R'=250/0.2*0.2=6250 Ohm
here k=N2/N1=10/50=0.2
hence R'=250/0.2*0.2=6250 Ohm
Sandeep Kumar said:
9 years ago
N2/N1= Sq.rt(R2/R1)
10/50 = Sq.Rt(250/R1)
(1/5)^2 = 250/R1.
R1=250*25 = 6250.
10/50 = Sq.Rt(250/R1)
(1/5)^2 = 250/R1.
R1=250*25 = 6250.
(1)
Prakash. D. said:
1 decade ago
Turns ratio K= n1/n2= 50/10
K=5,
w.k.t..., R1/R2=K^2
R1=250*25
R1=6250 ohms.
K=5,
w.k.t..., R1/R2=K^2
R1=250*25
R1=6250 ohms.
TUTUN MONDAL said:
8 years ago
K=N2/N1=1/5.
SECONDARY TO PRIMARY R1=R2/K^2 =250/(1/5)^2=250*25=6250OHMS.
SECONDARY TO PRIMARY R1=R2/K^2 =250/(1/5)^2=250*25=6250OHMS.
(5)
Pinnapareddy .sandhya lakshmi said:
1 decade ago
r1=r2/k^2
k=n2/n1=10/50=1/5
r2=250
r1=250/(1/5)^2=6250
r1=6250
k=n2/n1=10/50=1/5
r2=250
r1=250/(1/5)^2=6250
r1=6250
Bhagyashree said:
1 decade ago
R2=250
k=n1/n2=50/10
R1=R2*k^2
=250*(2500/100)
R1=6250ohm
k=n1/n2=50/10
R1=R2*k^2
=250*(2500/100)
R1=6250ohm
Mahendra dhakchavle said:
1 decade ago
R2=250
k=n1/n2=50/10
R1=R2*k^2
=250*(2500/100)
R1=6250ohm
k=n1/n2=50/10
R1=R2*k^2
=250*(2500/100)
R1=6250ohm
Divij said:
1 decade ago
r1=(n1/n2)^2*r2
WHERE n1=50 , n2=10,r2=250
Ans: 6250
WHERE n1=50 , n2=10,r2=250
Ans: 6250
HRD said:
2 years ago
R1 = (N1/N2)^2 * RL,
R1 = (50/10)^2 * 250,
R1 = 6250.
R1 = (50/10)^2 * 250,
R1 = 6250.
(6)
Richa said:
5 years ago
Transformation ratio is N1 (Primary)/N2 (secondary).
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