Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 20)
20.
When a 200 
load resistor is connected across the secondary winding of a transformer with a turns ratio of 4, the source "sees" a reflective load of
load resistor is connected across the secondary winding of a transformer with a turns ratio of 4, the source "sees" a reflective load of50
12.5
800
0
Discussion:
12 comments Page 1 of 2.
Satish said:
1 decade ago
source sees a reflective load= with respect to primary.
Hence, 200/16=12.5 (z/k*k)
Hence, 200/16=12.5 (z/k*k)
Motiur said:
1 decade ago
As k=rt of r1/r2
Tarnjeet Singh said:
1 decade ago
Please explain it.
Vasu said:
1 decade ago
k = sqrt (R/r)
4 = sqrt (200/r)
16 = 200/r
r = 12.5
4 = sqrt (200/r)
16 = 200/r
r = 12.5
Raju saikh said:
1 decade ago
Turns ratio=k= n2/n1
& n2/n1=sqrt(r2/r1)
so, k=sqrt(r2/r1)
k*k=(r2/r1)
here, r2=200ohm;& k=4
so, 4*4=(200/r1)
r1=200/16
=12.5
& n2/n1=sqrt(r2/r1)
so, k=sqrt(r2/r1)
k*k=(r2/r1)
here, r2=200ohm;& k=4
so, 4*4=(200/r1)
r1=200/16
=12.5
Rani said:
1 decade ago
What is correct formula to this problem?
Jagadeesh said:
10 years ago
Turns ratio k = N1/N2,
Transformation ratio K (capital k) = N2/N1.
So, K = 1/k.
R2' = R2/K^2;
Here K = 1/k = 1/4;
R2' = 200/(1/4)^2 = 3200, which is not in option.
Transformation ratio K (capital k) = N2/N1.
So, K = 1/k.
R2' = R2/K^2;
Here K = 1/k = 1/4;
R2' = 200/(1/4)^2 = 3200, which is not in option.
Ranjan said:
9 years ago
How to solve the below problem, can anyone help me?
Suppose that two AC waves have the same frequency but differ in phase by exactly 1/20 of a cycle. What is the phase difference between these two waves?
Suppose that two AC waves have the same frequency but differ in phase by exactly 1/20 of a cycle. What is the phase difference between these two waves?
Shiju said:
9 years ago
@Jagadeesh answer is very correct explanation.
If turns ratio 4 means vp/vs = 4 i.e vp = 4 * vs. If 200 ohm load then vs/200 is the current drawn at secondary So at primary the current Ip will be 1/4 of secondary current = vs/200/4 = vs/800.
Then reflective load = Vp/Ip = 48Vs/Vs/800 = 3200.
If turns ratio 4 means vp/vs = 4 i.e vp = 4 * vs. If 200 ohm load then vs/200 is the current drawn at secondary So at primary the current Ip will be 1/4 of secondary current = vs/200/4 = vs/800.
Then reflective load = Vp/Ip = 48Vs/Vs/800 = 3200.
Shiju said:
9 years ago
@Ranjan,
I think it will be 18 degrees i.e total 360 degrees so 360/20 = 18.
I think it will be 18 degrees i.e total 360 degrees so 360/20 = 18.
(2)
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