### Discussion :: Transformers - General Questions (Q.No.20)

Satish said: (Dec 10, 2010) | |

source sees a reflective load= with respect to primary. Hence, 200/16=12.5 (z/k*k) |

Motiur said: (Dec 16, 2011) | |

As k=rt of r1/r2 |

Tarnjeet Singh said: (Jan 6, 2012) | |

Please explain it. |

Vasu said: (Feb 5, 2012) | |

k = sqrt (R/r) 4 = sqrt (200/r) 16 = 200/r r = 12.5 |

Raju Saikh said: (Oct 13, 2012) | |

Turns ratio=k= n2/n1 & n2/n1=sqrt(r2/r1) so, k=sqrt(r2/r1) k*k=(r2/r1) here, r2=200ohm;& k=4 so, 4*4=(200/r1) r1=200/16 =12.5 |

Rani said: (Sep 7, 2014) | |

What is correct formula to this problem? |

Jagadeesh said: (Dec 13, 2015) | |

Turns ratio k = N1/N2, Transformation ratio K (capital k) = N2/N1. So, K = 1/k. R2' = R2/K^2; Here K = 1/k = 1/4; R2' = 200/(1/4)^2 = 3200, which is not in option. |

Ranjan said: (Apr 22, 2016) | |

How to solve the below problem, can anyone help me? Suppose that two AC waves have the same frequency but differ in phase by exactly 1/20 of a cycle. What is the phase difference between these two waves? |

Shiju said: (Oct 25, 2016) | |

@Jagadeesh answer is very correct explanation. If turns ratio 4 means vp/vs = 4 i.e vp = 4 * vs. If 200 ohm load then vs/200 is the current drawn at secondary So at primary the current Ip will be 1/4 of secondary current = vs/200/4 = vs/800. Then reflective load = Vp/Ip = 48Vs/Vs/800 = 3200. |

Shiju said: (Oct 25, 2016) | |

@Ranjan, I think it will be 18 degrees i.e total 360 degrees so 360/20 = 18. |

Amani Naidu said: (Feb 16, 2017) | |

Clear explanation, Thanks @Jagadeesh. Answer is 3200. |

Ali Butt said: (Aug 4, 2019) | |

R2=R1k^2. R1=R2/k^2. R1=200/(4)^2. R1=200/16. R1=12.5. |

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