Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 9)
9.
If 25 W of power are applied to the primary of an ideal transformer with a turns ratio of 10, the power delivered to the secondary load is
Discussion:
58 comments Page 2 of 6.
Anshul soni said:
1 decade ago
First of all power factor is not given which is different for input side and output side. So active power can never be equal apparent power can only be equal KVA should be equal on both sides not KW. Whether it is ideal or practical we can't say active power is equal or not.
Vijay kumar said:
1 decade ago
For ideal T/F, efficiency 100%.
Hence o/p = i/p.
i.e, 25.
Hence o/p = i/p.
i.e, 25.
Gurbachan Dhiman said:
1 decade ago
In a ideal TXR does not any type loss so that i/p power = o/p power.
Sanawaz said:
1 decade ago
V1I1 = V2I2 (for IDEAL transformer) means power constant.
M MOUNIKA said:
1 decade ago
@Srinivas.
Transformer is a constant flux power and frequency but for practical transformer we have to calculate core losses and copper losses and output = input-total losses from this calculate efficiency = output/input.
Transformer is a constant flux power and frequency but for practical transformer we have to calculate core losses and copper losses and output = input-total losses from this calculate efficiency = output/input.
Guna said:
1 decade ago
Its so simple an ideal transformer is free from losses so whatever the power is supplied to the primary winding the same power is delivered at output. So its obviously 25w.
Piyush said:
1 decade ago
Because this Transformer is IDEAL transformer. Then no loss in the ideal transformer.
Chan said:
9 years ago
Why they give turns ratio?
Sadashiv said:
9 years ago
In a transformer the ratio of primary to secondary is 9 : 4 if power input is P, what will be the ratio of power output to the power input?
Md nayan said:
9 years ago
i/p power 10V then o/p 10v is called ideal transformer.
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