Electrical Engineering - Time Response of Reactive Circuits - Discussion
Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 2)
2.
An integrator consists of a 3.3 k
resistor and a 2 
F capacitor. A single 30 V, 6 ms pulse is applied to the input. How much will the capacitor charge?
resistor and a 2 F capacitor. A single 30 V, 6 ms pulse is applied to the input. How much will the capacitor charge?Discussion:
7 comments Page 1 of 1.
JOSHI said:
1 decade ago
If capacitor connected series with resistance then?
Shazia said:
1 decade ago
RC integrator response is given as v(1-e^-t/rc).
Salma Hisham said:
1 decade ago
Voltage at capacitor when charging = V(total) * [ 1 - exp(-t/RC) ].
R = 3.3K && C=2 micro.
Then ==> RC= 6.6 ms.
Vc = 30 * [ 1 - exp (-6/6.6) ].
Vc = 17.91 v.
R = 3.3K && C=2 micro.
Then ==> RC= 6.6 ms.
Vc = 30 * [ 1 - exp (-6/6.6) ].
Vc = 17.91 v.
Sudhin said:
9 years ago
Can you please describe it?
Subrat said:
9 years ago
I can't understand this. Please explain in detail.
Anubhav Chaudhary said:
8 years ago
R=3.3 * 10^3 Ohms
C=2 * 10^-6 F
T= 6 * 10^-3 =0.006 sec
t = RC
=3.3 * 10^3 * 2 * 10^-6
= 0.0066 sec.
Then,
Change = (Final-start) * (1-1/e^T/t).
= (30 - 0) * (1-1/e^0.006/0.0066).
= (30) * (1-1/e^0.9090).
= 30 * 0.5970.
= 17.91.
C=2 * 10^-6 F
T= 6 * 10^-3 =0.006 sec
t = RC
=3.3 * 10^3 * 2 * 10^-6
= 0.0066 sec.
Then,
Change = (Final-start) * (1-1/e^T/t).
= (30 - 0) * (1-1/e^0.006/0.0066).
= (30) * (1-1/e^0.9090).
= 30 * 0.5970.
= 17.91.
(3)
Raghavendra c n said:
3 years ago
@Anubhav.
Thanks for solving it.
Thanks for solving it.
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