Electrical Engineering - Three-Phase Systems in Power Applications - Discussion
Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 4)
4.
In a certain three-wire Y-connected generator, the phase voltages are 2 kV. The magnitudes of the line voltages are
Discussion:
32 comments Page 2 of 4.
Musahak khan said:
9 years ago
Phase voltage = 2000v.
So,line voltage = root3 * 2000 volt,
= 3464volt.
So,line voltage = root3 * 2000 volt,
= 3464volt.
Musahak khan said:
9 years ago
Phase voltage = 2000v.
So,line voltage = root3 * 2000 volt,
= 3464volt.
So,line voltage = root3 * 2000 volt,
= 3464volt.
Musahak khan said:
9 years ago
Phase voltage = 2000v.
So,line voltage = root3 * 2000 volt,
= 3464volt.
So,line voltage = root3 * 2000 volt,
= 3464volt.
Ajakpogha Ferdinand O. said:
1 decade ago
Vl=root3*Vph
= 1.7320*2000
= 3,464.1016V
where Vl=Line Voltage
Vph=Phase Voltage
= 1.7320*2000
= 3,464.1016V
where Vl=Line Voltage
Vph=Phase Voltage
VARADHA SIT said:
1 decade ago
VL= ROOT 3 INTO VP.
VP = 2KV = 2000V.
ROOT3 = 1.732.
VL = 1.732 [2000] = 3464.
VP = 2KV = 2000V.
ROOT3 = 1.732.
VL = 1.732 [2000] = 3464.
Venkidu said:
1 decade ago
VL is equal to the Vph.
VL = root3*Vph.
= 1.732*2000.
= 3464.1016V.
VL = root3*Vph.
= 1.732*2000.
= 3464.1016V.
Sanjay verma said:
1 decade ago
Line voltage = root three phase voltage, so 1.732*2000 = and is 3464.
Manohar kr. gaur said:
1 decade ago
We know,
vl=root3*vph
then,vl=2000*1.732
=3464.10 volts
vl=root3*vph
then,vl=2000*1.732
=3464.10 volts
Gajendra Singh said:
1 decade ago
WKT
V(line)=root3* V(Phase)
i.e.
V(line)=root3*2100
=3464.10volts
V(line)=root3* V(Phase)
i.e.
V(line)=root3*2100
=3464.10volts
Sandeep wasnik said:
1 decade ago
vl = root three*vph.
= 1.73*2kv.
= 1.73*2000.
= 3460 volt.
= 1.73*2kv.
= 1.73*2000.
= 3460 volt.
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