Electrical Engineering - Three-Phase Systems in Power Applications - Discussion
Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 4)
4.
In a certain three-wire Y-connected generator, the phase voltages are 2 kV. The magnitudes of the line voltages are
Discussion:
32 comments Page 2 of 4.
Ajakpogha Ferdinand O. said:
1 decade ago
Vl=root3*Vph
= 1.7320*2000
= 3,464.1016V
where Vl=Line Voltage
Vph=Phase Voltage
= 1.7320*2000
= 3,464.1016V
where Vl=Line Voltage
Vph=Phase Voltage
Puni said:
1 decade ago
What about in delta conn?
Chado said:
1 decade ago
In wye connection: Line voltage = square root of 3 multiplied to Phase voltage while Line current = Phase current
In delta connection: Line current = square root of 3 multiplied to Phase current while Line voltage = Phase voltage
In delta connection: Line current = square root of 3 multiplied to Phase current while Line voltage = Phase voltage
Venkidu said:
1 decade ago
VL is equal to the Vph.
VL = root3*Vph.
= 1.732*2000.
= 3464.1016V.
VL = root3*Vph.
= 1.732*2000.
= 3464.1016V.
VARADHA SIT said:
1 decade ago
VL= ROOT 3 INTO VP.
VP = 2KV = 2000V.
ROOT3 = 1.732.
VL = 1.732 [2000] = 3464.
VP = 2KV = 2000V.
ROOT3 = 1.732.
VL = 1.732 [2000] = 3464.
Sanjay verma said:
1 decade ago
Line voltage = root three phase voltage, so 1.732*2000 = and is 3464.
Saleem pasha said:
1 decade ago
Line voltage = root3 times phase voltage.
Vishal said:
1 decade ago
Why come 1.732 please answer I m not understand?
ARUNPANDIYAN M said:
1 decade ago
VL = 1.732*VPH.
VL = 1.732*2000.
VL = 3464.
VL = 1.732*2000.
VL = 3464.
Rajiv gandhi said:
1 decade ago
In a three phase system star connection line voltage is root of three so 2000kv multiply with root of three. It is right answer.
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