Electrical Engineering - Three-Phase Systems in Power Applications - Discussion
Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 9)
9.
A two-phase generator is connected to two 90 
load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?
load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?Discussion:
63 comments Page 6 of 7.
Ganapathi said:
1 decade ago
In = (120/90)+(120<-90/90).
= 240/90.
= 2.66.
= 240/90.
= 2.66.
Prashant said:
1 decade ago
Can you give the circuit diagrm? or solve the problem.
Ajeet shukla said:
1 decade ago
@Sukvinder please explain in detail how you get this?
Indradeo kumar said:
1 decade ago
Please give the explaination of this answer.
Sayed Tousif Pasha said:
1 decade ago
Whether the load is in series or parallel.
Rachappa said:
9 years ago
Is there any formula to find this answer?
Ali said:
9 years ago
According to me, the answer is 2.66.
Vikram said:
1 decade ago
Please explaination of this answer.
Shivaraj said:
8 years ago
Give me the correct explanation!
(1)
Sandeep said:
1 decade ago
Can you give the circuit diagrm?
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