Electrical Engineering - Three-Phase Systems in Power Applications - Discussion
Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 9)
9.
A two-phase generator is connected to two 90
load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?

Discussion:
63 comments Page 4 of 7.
Saheb said:
1 decade ago
Suppose, open delta connection neutral i = i/3^1/2.
Here, i = (120/90) + (120/90) = 2.66 A.
Neutral i = 2.66/3^1/2 = 1.54~1.77 A.
Here, i = (120/90) + (120/90) = 2.66 A.
Neutral i = 2.66/3^1/2 = 1.54~1.77 A.
Shankar yadav said:
8 years ago
V = IR.
Total resistance of two resistors(is parallel) is:
45ohms,
Voltage is 120v,
Current is =120/45,
Current is 2.66 amps.
Total resistance of two resistors(is parallel) is:
45ohms,
Voltage is 120v,
Current is =120/45,
Current is 2.66 amps.
(1)
Sandeep wasnik said:
1 decade ago
There are the two phase and hence,
120*120 = 14400 volt.
90*90 = 8100 ohm.
Hence current (i) = v/r.
= 14400/8100 = 1.77 amp.
120*120 = 14400 volt.
90*90 = 8100 ohm.
Hence current (i) = v/r.
= 14400/8100 = 1.77 amp.
Minakshi Khushoo said:
1 decade ago
I agree with @Dawid. The answer should be B. Because the two currents will be in quadrature owing to the given 2 phase supply.
Amjad moawia said:
9 years ago
There is the two phase.
120*120 = 14400 volt.
90*90 = 8100 ohm.
Hence current (i) = v/r.
= 14400/8100 = 1.77 amp.
120*120 = 14400 volt.
90*90 = 8100 ohm.
Hence current (i) = v/r.
= 14400/8100 = 1.77 amp.
(2)
RUPESH S BORADE said:
1 decade ago
If 2 resistance are in parallel then.
(90*90)/180 = 45.
I = V/R.
I = 120/45.
I = 2.66.
That's answer is C.
(90*90)/180 = 45.
I = V/R.
I = 120/45.
I = 2.66.
That's answer is C.
Sachin said:
1 decade ago
Please give proper solution.
That justify answer is 1.77.
Because by calculations answer will come 1.88.
That justify answer is 1.77.
Because by calculations answer will come 1.88.
Mac. F. Crasto said:
1 decade ago
When the load is balance Zero current flows through the neutral line.since neutral is common to both load.
NASR said:
10 years ago
Right answer is D because:
1 = 120/90a with angle 0+120/90 with angle 120.
= 1.33+j0-0.665+j1.152.
1 = 120/90a with angle 0+120/90 with angle 120.
= 1.33+j0-0.665+j1.152.
Parveen kumar said:
1 decade ago
There is 2 phase so voltage 120x120 = 14400.
2R = 90X90 = 8100.
I = V/R.
S0 = 14400/8100 = 1.77.
2R = 90X90 = 8100.
I = V/R.
S0 = 14400/8100 = 1.77.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers