Electrical Engineering - Three-Phase Systems in Power Applications - Discussion
Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 9)
9.
A two-phase generator is connected to two 90 
load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?
load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?Discussion:
63 comments Page 2 of 7.
Parihar said:
8 years ago
120 * 120 ÷90 * 90 = 1.77.
Shankar yadav said:
8 years ago
V = IR.
Total resistance of two resistors(is parallel) is:
45ohms,
Voltage is 120v,
Current is =120/45,
Current is 2.66 amps.
Total resistance of two resistors(is parallel) is:
45ohms,
Voltage is 120v,
Current is =120/45,
Current is 2.66 amps.
(1)
Sasikumar paramasivam said:
8 years ago
The current in each phase is 120/90 = 1.33a.
For two-phase system, the resultant current at the common line is root(2) of phase current which is 1.88a.
For two-phase system, the resultant current at the common line is root(2) of phase current which is 1.88a.
Ali said:
9 years ago
the correct answer is (B) as:
This is a two phase system gnerator with source voltage:
Va = 120 with zero angle & Vb with angle 90 degrees, thus the nutral current is as follows
In = Va /90 + Vb / 90 = (120/_0)/90 + (120/_90) = 1.33 + j1.33 = 1.88.
This is a two phase system gnerator with source voltage:
Va = 120 with zero angle & Vb with angle 90 degrees, thus the nutral current is as follows
In = Va /90 + Vb / 90 = (120/_0)/90 + (120/_90) = 1.33 + j1.33 = 1.88.
Ali said:
9 years ago
According to me, the answer is 2.66.
Aditya bakshi said:
9 years ago
I think the answer is c, if the answer is D please give me the correct explanation.
Suryabai said:
9 years ago
Which is the correct answer? Please tell the correct option.
Rachappa said:
9 years ago
Is there any formula to find this answer?
Ayush Kumar said:
9 years ago
It is simple question since, two phase generator is connected to two load resistor therefore resistance = 90 * 90 = 8100 & total voltage = 120 * 120 = 14400.
Therefore required current through common neutral line is = 14400/8100 = 1.77A.
Therefore required current through common neutral line is = 14400/8100 = 1.77A.
(2)
Awesome said:
9 years ago
@Amjad.
How have you done this. Is there any formula like that?
How have you done this. Is there any formula like that?
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