Electrical Engineering - Series-Parallel Circuits - Discussion

Five 1k ohm parrallel R=200..
i =V/R =50/200=0.25.
i for 1k, i = 50/1000 = 1/20 = 0.05.
i %=0.05 * 100/0.25 = 20%.

From Priya calculations, we get:

Current in circuit = .089 A.

Total resistance in parallel combination of 5 1 Kohm resistors = 200 Ohm.

So, voltage in parallel of 5 1kohm resistor = I x R(total res of paralleled 5 resistors).

= .089 x 200.

= 17.8 V.

For parallel combinations, V = V1 = V2 = V3 = V4.

So. V1 = I1 R1.

I1 = V1/R1 = 17.8/(1x10^3) = 0.0178 A.

For percentage, I1/whole circuit current x 100% = 0.0178/.089 x 100.

= 0.2 x 100.

= 20%.

470ohm and 1500ohm are in parallel hence effective resitance is=470*1500/1970
=357.87ohm

Parallel combination of 5 1kohm resistors=1000/5=200ohm

Now toatal effective resistance=357.87+200=557.87ohm

Hence current in the circuit=50/557.87=.089amp

Now current throuh 5 1kohm resistors can be divided into two parallelcombination one with resistance 1kohm and other with 1/4kohm...........

Hence by current divider rule current through 1kohm resistor=(.089*1/4)/(1+1/4)=.018amp

Hence % = (.018/.089)*100 = 20%.

Actually, they ask for a percentage. So, for 51K ohms resistor 50V/200ohm = 0.25A.
Again 50/1 Kohm = 0.05A, therefore 0.05/0.25*100 = 20%.

The simplest way is to decide the correct ans. is the total current is passed through five parallel 1k resister equal amount bcoz the same value of resister so 1k current flow=total current (%)/number of resister; 20%.

Can anybody explain me about the answer?

Thanks @Rohit.

Please somebody give me current divider formula with explanation.

Thank you @Meenakshi.

Thanks for the explanation of the answer.