Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 8)
8.
The parallel combination of a 470 
resistor and a 1.5 k resistor is in series with the parallel combination of five 1 k resistors. The source voltage is 50 V. The percentage of the load current through any single 1 k resistor is
resistor and a 1.5 k resistor is in series with the parallel combination of five 1 k resistors. The source voltage is 50 V. The percentage of the load current through any single 1 k resistor isDiscussion:
22 comments Page 3 of 3.
Meena said:
1 decade ago
Current I flowing in the circuit will be divided into 5 equal parts (as the 5 equal valued resistors are connected in parallel).
So the current in each branch (of resistor) is I/5.
So the percentage is : (I/5) /I*100 = 20%.
So the current in each branch (of resistor) is I/5.
So the percentage is : (I/5) /I*100 = 20%.
Snehal said:
1 decade ago
Thanks rohit.
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