Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 9)
9.
A certain Wheatstone bridge has the following resistor values: R1 = 10 k
, R2 = 720 , and R4 = 2.4 k. The unknown resistance is
, R2 = 720 , and R4 = 2.4 k. The unknown resistance is24
2.4
300
3,000
Discussion:
28 comments Page 1 of 3.
Abinash said:
3 years ago
R1/R2=R3/R4.
Or
R3=(R1/R2). R4
Ans =33.33k ohm.
Or
R3=(R1/R2). R4
Ans =33.33k ohm.
(2)
Haseeb said:
4 years ago
Wheatstone bridge.
R1R2=R3R4.
Here unknown resistance is R3.
So,
R3 = R1R2/R4.
= 10000 * 720/2400.
R3 = 3000 ohm.
R1R2=R3R4.
Here unknown resistance is R3.
So,
R3 = R1R2/R4.
= 10000 * 720/2400.
R3 = 3000 ohm.
(4)
Engr Baloch said:
5 years ago
Agree @Jojo D.
The answer should be 33.33k Ohms, because the formula is R1/R2=R3/R4.
The answer should be 33.33k Ohms, because the formula is R1/R2=R3/R4.
Jojo D. said:
5 years ago
The answer should be 33.33 k Ohms.
To picture out the circuit, let Nodes A and B are connected across the positive and negative sides of the source respectively. The standard circuit configuration is drawn such that R1 and R2 are connected in series, with the other end of R1 connected to Node A and the other end of R2 connected to Node B. R3 and R4 are also connected in series with the other end of R3 connected Node A and the other end of R4 connected to Node B.
Now, we have a clear picture showing us how the four resistors are inter-connected in the circuit. Based on this configuration, we can derive that R1/R2=R3/R4.
Therefore, R3=(R1R4)/R2. Hence, the answer should be 33.33 kOhms.
To picture out the circuit, let Nodes A and B are connected across the positive and negative sides of the source respectively. The standard circuit configuration is drawn such that R1 and R2 are connected in series, with the other end of R1 connected to Node A and the other end of R2 connected to Node B. R3 and R4 are also connected in series with the other end of R3 connected Node A and the other end of R4 connected to Node B.
Now, we have a clear picture showing us how the four resistors are inter-connected in the circuit. Based on this configuration, we can derive that R1/R2=R3/R4.
Therefore, R3=(R1R4)/R2. Hence, the answer should be 33.33 kOhms.
W.b said:
5 years ago
R1/R2 = R3/R4.
THIS IS CORRECT FORMULA.
THIS IS CORRECT FORMULA.
Darshil said:
6 years ago
The correct formula is R1/R2 = R3/R4.
So the answer comes 33.3kOhm.
So the answer comes 33.3kOhm.
Hardiksinh said:
6 years ago
Yes, R3 = 33.33, because the formula is R1R4=R2R3. Then R3= R1R4/R2.
MARI RAJ said:
6 years ago
Unknown resister R3=(R1/R2)*R4.
So, R3 = 33.3kohm.
So, R3 = 33.3kohm.
Jagan said:
7 years ago
I am not getting it. Please explain it.
Aditya said:
8 years ago
No, the correct answer is 33.3kohm.
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