Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 9)
9.
A certain Wheatstone bridge has the following resistor values: R1 = 10 k
, R2 = 720 , and R4 = 2.4 k. The unknown resistance is
, R2 = 720 , and R4 = 2.4 k. The unknown resistance is24
2.4
300
3,000
Discussion:
28 comments Page 3 of 3.
Ankit Tiwari said:
1 decade ago
Normal formula apply here R1/R2 = R3/R4.
Meenakshi said:
1 decade ago
Here Rv means variable resistance i.e., generally R3.
Formula R4 = R2R3/R1, but here R4 is given, we have to fnd R1, so eqn becomes R1 = R2R3/R4.
Therefore R1 = 720*10k/2.4K = 3000 ohms.
Formula R4 = R2R3/R1, but here R4 is given, we have to fnd R1, so eqn becomes R1 = R2R3/R4.
Therefore R1 = 720*10k/2.4K = 3000 ohms.
Keerthi said:
1 decade ago
Here Rv means R1 or R3?
Tamilarasan said:
1 decade ago
In a wheatstone bridge the ratio is equal (i.e. R1*R2=R3*R4).
So R2=R3*R4/R1. Sub the value. We will get the answer.
So R2=R3*R4/R1. Sub the value. We will get the answer.
Sai said:
1 decade ago
I agree with you anand.
Anand said:
1 decade ago
(R1/R2)=(R3/R4),So R4=(R2/R1)*R3
Ramu said:
1 decade ago
This will ans is correct but procedure is wrong.
Wheat stone bridge Rx= (R2/R1) *R3.
Wheat stone bridge Rx= (R2/R1) *R3.
Lavanya said:
1 decade ago
Explanation please?
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