Electrical Engineering - Series-Parallel Circuits - Discussion

Explanation please.

We need to equally devide the source or partially divide the source. the source voltage is 6v.

Here give ans are; 2+4=6; 2+2=4, 2+6=8, 4+6=10.

We need the total voltage of 6v at the end of the result.

Because our total voltage given is 6.

So please pick the ans from given four answers.

Explain the question please.

Two 2.2 reg are in parallel [1.1] and series with 3rd reg.[2.2] after this apply voltage divider rule.

@Vimal I want to know If any option of 3+3 is given then what is the correct answer 3+3 or 2+6.

@ Parneet, it will be 2 + 4 only.

Let us say all 3 resistors connected in series and connected to the source. We have a condition that it have only two taps in the load, so obviously we have 2.2 K Ohm and 4.4 K Ohm, and the voltage across them is 2 and 4 V respectively.

Please clarif it in simplest way.

It is given as threes resistors are used each with rating 2.2kohm.

From the question, we can infer that it is a voltage divider circuit( A 6 V battery output is divided down to obtain two output voltages)

voltage divider circuit consists of 2 impendence and the output is taken across from the mid point

so the three res can be in 2 different combination ( 2 res parallel , 1 load res) or (2 res in series and 1 load res).

2 res parallel and 1 load res ===>> (2.2*2.2)/(2.2+2.2) = 1.1 + the load res 2.2
vout = (z2 *vin)/(z2+z1) = (2.2 * 6)/(2.21.1) = 4 v
**** anothe case (2 res series + 1 load res)
2.2+2.2 = 4.4 and 1 load res 2.2,
vout = (2.2*6)/(2.2+4.4)= 2 v.

So 2v and 4 v are the possible outcomes of three res in different combination.

Thank you @Naveen.

Nice @Naveen.