Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 5)
5.
A voltage divider consists of two 68 k
resistors and a 24 V source. The unknown output voltage is
resistors and a 24 V source. The unknown output voltage isDiscussion:
40 comments Page 3 of 4.
CIRCUIT BREAKER said:
1 decade ago
Unknown out put voltage = (24*68)/(68+68).
= 12v.
= 12v.
Sakthi said:
1 decade ago
In voltage divider the resistors will be in series. So to find the voltage across any resistor just apply the voltage divider rule. Another way is, find the total resistance and the current, then by using OHM's law we can easily find the voltage across each resistor.
K vamsi said:
1 decade ago
Hello @Subhojit,
In this question these 2 resistors are in series and same value so voltage across any of the resistor is same I think if it is wrong tell me with clarity.
In this question these 2 resistors are in series and same value so voltage across any of the resistor is same I think if it is wrong tell me with clarity.
Subhojit said:
1 decade ago
A voltage divider consists of two 68 k resistors and a 24 V source.
The unknown output voltage is:
In this question there is no specification that the Vout is across which resistor that is whether it is across r1: 68 ohm or r2: 68 ohm or across r1+r2 : 136 ohm. So answer may be 12v or 24v. Data insufficient.
The unknown output voltage is:
In this question there is no specification that the Vout is across which resistor that is whether it is across r1: 68 ohm or r2: 68 ohm or across r1+r2 : 136 ohm. So answer may be 12v or 24v. Data insufficient.
Jadecliff said:
1 decade ago
From my opinion,
In series, total voltage is the sum of individual voltages.
V1 is the voltage output after the current I which is the same in series passes through the resistor R1(68).
R(total) = 68+68 = 2 x 68.
We know total voltage supplied is 24.
V(total) = I * R(total).
I = 24 x 1/(2x68) = 12/68.
I = I1 = I2.
So V2 = I x R2 (V2 = output voltage after passing R2).
= 12/68 x 68.
= 12 V.
In series, total voltage is the sum of individual voltages.
V1 is the voltage output after the current I which is the same in series passes through the resistor R1(68).
R(total) = 68+68 = 2 x 68.
We know total voltage supplied is 24.
V(total) = I * R(total).
I = 24 x 1/(2x68) = 12/68.
I = I1 = I2.
So V2 = I x R2 (V2 = output voltage after passing R2).
= 12/68 x 68.
= 12 V.
Arundeep singh said:
1 decade ago
Voltage divider always in series combination so solve it by voltage divider method as 24 V/ 2 = 12 we as both are having equal value so voltage will be divide and current will remain same.
Mr. Kathiravan From Vellore said:
1 decade ago
Voltage Divider (Vout)=(R2/(R1+R2))xVin
= (68/(68+68))x24
= 12V
= (68/(68+68))x24
= 12V
Pratik shah said:
1 decade ago
Thanks sagata.
Sagata said:
1 decade ago
We know voltage in one of the 68 ohm resistor is V=I.R1(R1=resistance of one of the resistors )
again V=(V/R).R1(R=total resistance of circuit.)
Hence,V=[24/(68+68)]*68=12V
Voltage divider rule is applicable for series circuit only because in series only voltage varies but not in paralel circuits.
again V=(V/R).R1(R=total resistance of circuit.)
Hence,V=[24/(68+68)]*68=12V
Voltage divider rule is applicable for series circuit only because in series only voltage varies but not in paralel circuits.
Sri said:
1 decade ago
V2=V1R1(R1+R2) and putting the values we get 12
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