Electrical Engineering - Series-Parallel Circuits - Discussion

Thanks @Sushma.

I think here applying voltage division rules this used only for resistors connected with voltage source if not then the converted number of resisters is only 2 resistor formate so,

If you find.

R0 =Vi* (R1/R1+R2).
R0=24* (68/68+68) =12.

Vout=(R2/(R1+R2))Vin for a voltage divider,when a input voltage is applied across a series of resistors R1&R2 and ouput is the voltage applied across R2.
here,Vin=24V,R1=R2=68ohms,
so,Vout=(68/(68+68))24
=12V

Thanks sushma.

In a voltage divider circuit there are always 2 resistors in series say r1 nd r2.

The output is taken across say r2.

Then the output voltage will be;

Vo=(r2/r2+r1)vi.
Vi is input voltage.
Therefore;
Vo=(68/68+68)24=24/2=12.

Voltage divider general formula:

Vout = (Z2/(Z1+Z2))*Vin.

Vout = (68/136)*24.

Vout = (1/2)*24.

Vout = 12.

Nice @Sushma.

It is totally wrong because output voltage means consumed voltage except source so answer is 24.

The output voltage changes with load resistance and it has not been given that the circuit is a closed circuit, so the output voltage will be 24 volts until and unless load is connected at output, Also voltage will not vary until and unless there is a flow current in the circuit. The calculations done in above explanation have been considered in parallel which is not correct. Even if voltmeter is connected across output the internal resistance of the volt meter will be in parallel with the two resistances of voltage divider.

He is not specifying individual divider o/p voltage. He ask only o/p voltage means 24v(consumed at series resistors).