Electrical Engineering - Series-Parallel Circuits - Discussion

Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 5)
5.
A voltage divider consists of two 68 k resistors and a 24 V source. The unknown output voltage is
12 V
24 V
0 V
6 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
40 comments Page 1 of 4.

Sadik said:   7 years ago
Thanks @Sushma.
(3)

SHITAL said:   3 years ago
I think here applying voltage division rules this used only for resistors connected with voltage source if not then the converted number of resisters is only 2 resistor formate so,

If you find.

R0 =Vi* (R1/R1+R2).
R0=24* (68/68+68) =12.
(1)

Nani said:   7 years ago
@All.

Hi, Here it is mentioned as a voltage divider. That means, its a simple series circuit across one voltage source.

Unless otherwise mentioning the output terminals, we cannot assume that the unknown voltage is across one of the resistance or so.

I think input data in the question has to be elaborated. Correct me, if I am wrong.
(1)

Sushma said:   1 decade ago
Vout=(R2/(R1+R2))Vin for a voltage divider,when a input voltage is applied across a series of resistors R1&R2 and ouput is the voltage applied across R2.
here,Vin=24V,R1=R2=68ohms,
so,Vout=(68/(68+68))24
=12V
(1)

Ganeshbabu said:   1 decade ago
Thanks sushma.
(1)

Viswa said:   9 years ago
Great answer @Sushma.
(1)

Ameesh devwrat said:   9 years ago
In a voltage divider circuit there are always 2 resistors in series say r1 nd r2.

The output is taken across say r2.

Then the output voltage will be;

Vo=(r2/r2+r1)vi.
Vi is input voltage.
Therefore;
Vo=(68/68+68)24=24/2=12.
(1)

Shobitha K N said:   1 decade ago
Voltage divider general formula:

Vout = (Z2/(Z1+Z2))*Vin.

Vout = (68/136)*24.

Vout = (1/2)*24.

Vout = 12.
(1)

Preethi said:   10 years ago
Nice @Sushma.
(1)

Dasu Namburi said:   1 decade ago
It is totally wrong because output voltage means consumed voltage except source so answer is 24.


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