Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 5)
5.
A voltage divider consists of two 68 k
resistors and a 24 V source. The unknown output voltage is

Discussion:
40 comments Page 2 of 4.
Preethi said:
9 years ago
Nice @Sushma.
(1)
Prawin said:
9 years ago
Thanks @Sushma.
Karthik holla said:
9 years ago
In voltage divider circuit if the resistance are same then output will be half of input voltage.
Shobitha K N said:
10 years ago
Voltage divider general formula:
Vout = (Z2/(Z1+Z2))*Vin.
Vout = (68/136)*24.
Vout = (1/2)*24.
Vout = 12.
Vout = (Z2/(Z1+Z2))*Vin.
Vout = (68/136)*24.
Vout = (1/2)*24.
Vout = 12.
(1)
Augustin said:
10 years ago
How can solve answers is 12 V brief explain.
Arun said:
1 decade ago
Where we need to calculate output?
Dasu Namburi said:
1 decade ago
He is not specifying individual divider o/p voltage. He ask only o/p voltage means 24v(consumed at series resistors).
Dasu Namburi said:
1 decade ago
It is totally wrong because output voltage means consumed voltage except source so answer is 24.
Narender said:
1 decade ago
1st draw the circuit diagram of the question then you will get the answer simply by observing the circuit diagram.
S.c.mathur said:
1 decade ago
The output voltage changes with load resistance and it has not been given that the circuit is a closed circuit, so the output voltage will be 24 volts until and unless load is connected at output, Also voltage will not vary until and unless there is a flow current in the circuit. The calculations done in above explanation have been considered in parallel which is not correct. Even if voltmeter is connected across output the internal resistance of the volt meter will be in parallel with the two resistances of voltage divider.
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