Electrical Engineering - Series-Parallel Circuits - Discussion

The formula for output voltage is;

V (out) = V (In) [ (RL / (R1 + RL) ]

So, if we take 1M ohm then the result will be V (out) = V (In) (0.9).
And if we take 1k ohm then the result will be V (out) = V (In) (0.25).
So, the output voltage will be less affected if the resistance value will be more so the correct answer is 1M ohm.

Can anyone please explain it clearly.

If R is max then current I will be less thus least effect on the circuit.

The question is pertaining to Voltage Divider, hence: V(output) = V(input) * (R1 / (R1 + R2))
Since the question is the LEAST effect of the Output Voltage we can then assume any value for V(input) in the example below I used 5 Volts, R1 or R (load) is connected parallel to the 3 series resistor because that is how voltage divider works and example would be like this.

V (out) = 5V * (1M ohms / (3K ohms + 1M ohms) = the answer would be appromately equal to 5, since the output and input are almost of equal value then R (load) which is 1 M ohms has the LEAST effect on the circuit.

Use the rule of voltmeter impact on measured circuit.

The circuit is connected in series, so current is the same through each resistor is same....though all resistant are having the same value. Each resister will consume same power (i.e. I^2R) and the voltage drop across each resistor is same(i.e. v=IR).

Somebody explain this clearly? I can't understand.

Can anyone explain this?

By ohms law v=ir.
I=v/r.

I.e. I is inversely proportional to r.
Hence, when r is more than I is less but I is directly proportional to v hence v is also less. R=1Mohm is more in above options.

Please, someone explain me briefly. I don't understand still.