Electrical Engineering - Series-Parallel Circuits - Discussion

Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 7)
7.
A certain voltage divider consists of three 1 k resistors in series. Which of the following load resistors will have the least effect on the output voltage?
1 M
100 k
1 k
330
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
40 comments Page 4 of 4.

Harpreet Singh said:   1 decade ago
V=IR:
LET V (OUT) = IR (OUT)
When we increase output resistance highly. Then effect on output voltage is also high.
We have 1MOhm high value resistace which effects to output voltage high.
Hence Answer is 1 M Ohm.

Krishna said:   1 decade ago
2/2=1.

Rohit said:   1 decade ago
According to ohm's law: V=IR & I=V/R; so that output volt. is most affected when I is high & I is high when R is low, But output volt. is least affected when I is low so that R is high. R=1M

Saurabh K. Chhaya said:   1 decade ago
1K because all resisters are same value so ans is 'C'

A.Harish said:   1 decade ago
How it is possible. R1+R2=1000+3.

Suyash singh panwar said:   1 decade ago
Three 1 ohm resistor in series then total resistance is 3 ohm
knom we connect 1 Mohm resistor then appling voltage divider rule .

Vout= R2*Vin/R1+R2 = 1*1000 kHZ/1000+3 = 0.997
the 1Mohm resistor is least effect on the output.

Anand said:   1 decade ago
Can anybody explain briefly about the answer?

Ganeshbabu said:   1 decade ago
@Siva

How it is possible 1.1/1+1 = 2/2 =1 ?

Siva said:   1 decade ago
Output voltage = r1.r2/r1+r2 = 1.1/1+1 = 2/2 = 1 m ohms

Panneer said:   1 decade ago
Please explan to me this answer.


Post your comments here:

Your comments will be displayed after verification.