Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 7)
7.
A certain voltage divider consists of three 1 k
resistors in series. Which of the following load resistors will have the least effect on the output voltage?
resistors in series. Which of the following load resistors will have the least effect on the output voltage?Discussion:
40 comments Page 4 of 4.
Harpreet Singh said:
1 decade ago
V=IR:
LET V (OUT) = IR (OUT)
When we increase output resistance highly. Then effect on output voltage is also high.
We have 1MOhm high value resistace which effects to output voltage high.
Hence Answer is 1 M Ohm.
LET V (OUT) = IR (OUT)
When we increase output resistance highly. Then effect on output voltage is also high.
We have 1MOhm high value resistace which effects to output voltage high.
Hence Answer is 1 M Ohm.
Krishna said:
1 decade ago
2/2=1.
Rohit said:
1 decade ago
According to ohm's law: V=IR & I=V/R; so that output volt. is most affected when I is high & I is high when R is low, But output volt. is least affected when I is low so that R is high. R=1M
Saurabh K. Chhaya said:
1 decade ago
1K because all resisters are same value so ans is 'C'
A.Harish said:
1 decade ago
How it is possible. R1+R2=1000+3.
Suyash singh panwar said:
1 decade ago
Three 1 ohm resistor in series then total resistance is 3 ohm
knom we connect 1 Mohm resistor then appling voltage divider rule .
Vout= R2*Vin/R1+R2 = 1*1000 kHZ/1000+3 = 0.997
the 1Mohm resistor is least effect on the output.
knom we connect 1 Mohm resistor then appling voltage divider rule .
Vout= R2*Vin/R1+R2 = 1*1000 kHZ/1000+3 = 0.997
the 1Mohm resistor is least effect on the output.
Anand said:
1 decade ago
Can anybody explain briefly about the answer?
Ganeshbabu said:
1 decade ago
@Siva
How it is possible 1.1/1+1 = 2/2 =1 ?
How it is possible 1.1/1+1 = 2/2 =1 ?
Siva said:
1 decade ago
Output voltage = r1.r2/r1+r2 = 1.1/1+1 = 2/2 = 1 m ohms
Panneer said:
1 decade ago
Please explan to me this answer.
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