Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 3)
3.
The output of a certain voltage divider is 12 V with no load. When a load is connected, the output voltage
Discussion:
24 comments Page 2 of 3.
Hkg said:
6 years ago
When there is no load there is no current hence the internal resistance drop is zero. But when we connect a load current starts flowing. Hence some vol drop will appear across the internal resistance.
SwarNa said:
6 years ago
The output is measured across the load, if we assume ideal condition, the circuit with 0 resistance in wires, the entire voltage drops across the load so output voltage should remain constant.
LOi Bi said:
5 years ago
Vo = Vs (with no load).
By voltage divider.
Vo = Vs(R/(R+RL)) (with load).
RL = across the load.
So the Voltage OUTPUT WILL DECREASE!
ASSUME A VALUE SO THAT YOU WILL UNDERSTAND!
By voltage divider.
Vo = Vs(R/(R+RL)) (with load).
RL = across the load.
So the Voltage OUTPUT WILL DECREASE!
ASSUME A VALUE SO THAT YOU WILL UNDERSTAND!
Ashish said:
1 decade ago
Answer is A.
Because when we connect load than current drawn from grid will be increase. Than transmission losses will increase. So voltage at load side will decrease.
Because when we connect load than current drawn from grid will be increase. Than transmission losses will increase. So voltage at load side will decrease.
Shibam jha said:
1 decade ago
Initially supply voltage = output voltage.
After adding load:
Output voltage = [supply voltage - I*resistance of load] (from KVL).
So the output voltages decreases.
After adding load:
Output voltage = [supply voltage - I*resistance of load] (from KVL).
So the output voltages decreases.
Khalique said:
1 decade ago
Voltage divider V(Rx) = Vi*Rx/(Rt). According to me voltage should increase if we are measuring output voltage across the resistor having resistance Rx.
Roshan said:
1 decade ago
Answer is A.
In no load case the o/p voltage is 12v but when me connect a load across it takes some power (volt) due to that o/p voltage is decreases.
In no load case the o/p voltage is 12v but when me connect a load across it takes some power (volt) due to that o/p voltage is decreases.
Amresh said:
8 years ago
Think simple as voltage divider applied in series circuit so if we connect more load automatically voltage decreases because voltage is divided.
Rohit said:
1 decade ago
When we connect the load some voltage is drop at the load so total o/p volt. is decreases.
Raji said:
1 decade ago
@Shibam Jha.
I have some doubt. Why are you using this formula?
I have some doubt. Why are you using this formula?
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