Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 2)
2.
Two 1.2 k
resistors are in series and this series combination is in parallel with a 3.3 k resistor. The total resistance is
resistors are in series and this series combination is in parallel with a 3.3 k resistor. The total resistance is138
1,389
5,700
880
Discussion:
15 comments Page 1 of 2.
Tarakant mishra said:
1 decade ago
R1=1.2,R2=1.2 they are connected in series and R3=3.3 connected in parallel with R1&R2.
R1+R2=2.4K ohm
R2parallel (R1+R2)
Formula for parallel=(R1+R2)R3/(R1+R2)+R3
=2.4*3.3/2.4+3.3
=1.38947 K ohm
=1.38947*1000=1389.47 ohms
R1+R2=2.4K ohm
R2parallel (R1+R2)
Formula for parallel=(R1+R2)R3/(R1+R2)+R3
=2.4*3.3/2.4+3.3
=1.38947 K ohm
=1.38947*1000=1389.47 ohms
(2)
R.safiyullah said:
1 decade ago
1.2+1.2 = 2.4K.
(2.4*3.3)/(2.4+3.3) = 1.38947K.
1.38947/1000 = 1.389kohm.
(2.4*3.3)/(2.4+3.3) = 1.38947K.
1.38947/1000 = 1.389kohm.
(2)
Suresh mrcool said:
1 decade ago
Two resistors are in series.
1.2K ohm and 1.2K ohm.
Total Resistance in Series r=R1+R2=>1.2K ohm+1.2K ohm=2.4K ohm.
Then that is parrallel with 3.3K ohm.
Total resistance in Parallel=1/R=1/r+1/R3.
1/R=(1/2.4K ohm)+(1/3.3K ohm)=>R=1389.47 ohm.
1.2K ohm and 1.2K ohm.
Total Resistance in Series r=R1+R2=>1.2K ohm+1.2K ohm=2.4K ohm.
Then that is parrallel with 3.3K ohm.
Total resistance in Parallel=1/R=1/r+1/R3.
1/R=(1/2.4K ohm)+(1/3.3K ohm)=>R=1389.47 ohm.
(1)
Kumara gm said:
6 years ago
Good solution, Thanks all.
(1)
Lamba prashanth said:
5 years ago
@Deepika
You explained clearly, Thanks.
You explained clearly, Thanks.
(1)
Madhu metha said:
1 decade ago
Two resistors of value 1.2k ohm each in series can be added up. connected in parallel with 3.3.k ohm.
((2.4*3.3)/(2.4+3.3))*1000 = 1389.47 for k
((2.4*3.3)/(2.4+3.3))*1000 = 1389.47 for k
Deepika said:
1 decade ago
Two resistors of value 2.4k ohms
i.e 1.2+1.2=2.4k ohms
Therefore R1=2.4k ohms. This R1 is connected parallel with 3.3k ohms.
we asume 3.3k ohms=R2
The parallel formula is=(R1*R2)/(R1+R2)
=2.4*3.3/(2.4+3.3)
=7.92/5.7
=1.38947k ohms
To convert the killo ohms into ohms by multipication 1000
Therefore;
=1.38947*1000
=1389.47 ohms
i.e 1.2+1.2=2.4k ohms
Therefore R1=2.4k ohms. This R1 is connected parallel with 3.3k ohms.
we asume 3.3k ohms=R2
The parallel formula is=(R1*R2)/(R1+R2)
=2.4*3.3/(2.4+3.3)
=7.92/5.7
=1.38947k ohms
To convert the killo ohms into ohms by multipication 1000
Therefore;
=1.38947*1000
=1389.47 ohms
Anand said:
1 decade ago
Nice explaination Deepika & Madhu metha
Riya Thakur said:
1 decade ago
2 resistors in series formula is = R1+R2
so 1.2+1.2 = 2.4k ohm
nw it parellel wid 3.3k ohm
parellel formula is R1*R2/R1+R2
so 2.4+3.3/2.4+3.3=1.389k ohms
=1389 ohms
so 1.2+1.2 = 2.4k ohm
nw it parellel wid 3.3k ohm
parellel formula is R1*R2/R1+R2
so 2.4+3.3/2.4+3.3=1.389k ohms
=1389 ohms
Bhavesh Prajapati said:
1 decade ago
2 resistors in series formula is = R1+R2
so 1.2+1.2 = 2.4k ohm
now it parellel wid 3.3k ohm
parallel formula is R1*R2/R1+R2
so 2.4+3.3/2.4+3.3=1.389k ohms
killo ohms into ohms by multipication 1000
=1.38947*1000
=1389.47 ohms
=1389 ohms
so 1.2+1.2 = 2.4k ohm
now it parellel wid 3.3k ohm
parallel formula is R1*R2/R1+R2
so 2.4+3.3/2.4+3.3=1.389k ohms
killo ohms into ohms by multipication 1000
=1.38947*1000
=1389.47 ohms
=1389 ohms
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