Electrical Engineering - Series Circuits - Discussion

From the law,
Input voltage = output voltage,
We have,
Vr1 + Vr2 + Vr3 + Vr4 + Vr5 = Vout = 6. All values are zero except Vr3.
=> 0 + 0 + Vr3 + 0 + 0 = 6,
Hence, Vr3 = 6.

The answer is 6v.

> voltage is zero when current is zero or resistance is zero.
Current cannot be zero.
So resistance is zero, may be a short circuit across the resistors.

It is 6v.

Question states we have voltage to the circuit and Its equal to 6v. (No dead batteries ect. Sorry)

ALL EXCEPT r3 have zero voltage drop-- the question is stating r3 has a nonzero voltage drop. If all the other resistors have zero drops they have zero resistance-- like ideal wire.

So we only have a single resistor in the circuit r3.

If these resistors were in parallel you wouldn't have a circuit for long because you'd have 4 shorts. The question states a series circuit.

So, the voltage drop across a single resistor in a 6v circuit. Then the answer is 6v. No math required.

V = IR.
R = V/I,
V = I*V/I.
V = V=6V.

It is the correct answer.

Yes, you are correct @Abdul.

R3 is an open circuit, so all other resistor voltage is 0, r3 will show 6 voltage.

If all resistors (except R3 are) considered having zero ohm resistance, then this condition satisfies.

R3 is load.

We know in series,

V=V1+V2+V3+V4+V5
=>6=0+0+V3+0+0
=>V3=6v.

The series circuit current is same voltage is divided according to statement all resistor voltage drop is zero then voltage appears r3 resistor so r3=6v.